Using 2 RFID and implementing access control algorithms

Projects Programming
1

Hi everyone.

I want to make access control project with RFID reader in the gate, when family enter each member will have NFC tag , i want to register the parent and under them is the kids.
Where the kid is not allowed to exit unless the parent scan his tag.

How can i connect the tags ID of the kids with the parent so only his parent can allow him to exit not any parent.

I had been thinking for days to implement it but no idea came to me.

Also then i need another RFID reader where if one of the kid scan his tag it will add 5$ on the family balance and when the family exit they can pay all the balance.

I need suggestions or ideas

2

You can do it with if elif constructs. Each card has a separate ID. you keep the parent's cards in a separate list
Separate children's cards. It should not allow output if the incoming data is equal to a list on the subcard. Let the parent card allow it. Let it let you handle it with a simple if else structure, if you want me to explain it in more detail, just say it.

3

But the problem here is that any parent will open the gate for the child, i want them to be connected as a family.

Because then i want another RFID that when any member scan it , it will add 5$ on the family balance.

I was thinking about online database bit cant get my head around it.

4

Design your data model.

link a child's tag to the tag of a parent.
If necessary, make it possible to link to 2 parent tags.

if you store your data in RAM or EPPROM a simple structure might help.
Just as an idea

struct Keydata
{
  byte id;     // a unique number for all known tags >= 1 - omnit ID 0!
  byte uid[4]; // the UID/Tag number of this tag
  byte parentA; // if <> 0 that id will be the parent of this ID
};

Keydata keydata[] {
  {1, {1, 2, 3, 1}, 0}, // a client A
  {2, {1, 2, 3, 2}, 0}, // another client B
  {3, {1, 2, 3, 3}, 2}, // a child of client B
  {4, {1, 2, 3, 4}, 2}  // another child of client B
};
5

This sound very interesting approach, can ypu elaborate on the last part of the code.

Like the parent side, why each client would be 0 and kids 2?

I'm new to this data model

6

therefore I suggested you should draft your own data model. Mine is just an example.

all entrys (ID 1 .. ID 4) represent one key (or one person).
ID 1 has no relation to a parent
ID 2 has no relation to a parent
ID 3 is a child, therefore it needs a relation to another person - a parent. In the example it has an relation to ID 2.
ID 4 is a child, therefore it needs a relation to another person - a praent. In the example to ID 2.

7

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