Delta_G:
Like a laser beam? OK, I'm be fascetious but see what i mean? Is this a big beam? A small beam? A metal beam? A wooden beam?
It is a metal beam, but as I said, you can imagine a wooden beam, a rocket or a pencil, it will not affect the algorithm (if I understood what are you trying to suggest me)
Delta_G:
got link?
Yes, this is the link of the shaker: Mini Electrodynamic Shaker 7 lbf
Delta_G:
Got link? Which one are you wanting to use?
Yes, this is what I would use: Triaxial ICP Accelerometers
Delta_G:
That still doesn't tell me anything. All I know is that some math is happening somewhere, but nothing about what the hell it is supposed to accomplish or how it is calculated or anything. Just that some math is happening somewhere.
I will try to explain it with a practical example: Arduino drives the shaker with a variable voltage, let say 0.1V, 0.2V, 0.1V, 0.2V, and so on (the time step can be X seconds). The structure (metal beam) will start vibrating and so the accelerometer will read a certain signal. This signal is sent to Arduino and it is compared with a reference signal. If there is an error, so the input voltages are modified ad hoc (let say 0.05V, 0.1V, 0.05V and so on).
Delta_G:
Then you're hosed. The Arduino doesn't have any BNC connectors. So you'll either have to get some connectors and add them to the Arduino, or cut the connectors off and wire it up some other way.
This is exactly what I was asking, because I don't know if it is possible the connection
Delta_G:
Maybe if you told us what the heck this thing is it would help. Like back up and give us the 10,000 foot view. What is it? IS it an Earthquake predictor? Is it a part for a rocket to measure vibration? What the hell is it?
During environmental testing, generally can be required that the specimen (metal beam, in this case) will behave in a proper way (when excited). So what is the right excitation, in order to obtain that "proper response" of the structure?
Thank you for your suggestions! I just believed all these details could be "boring", sorry.