Voltage drop on a capacitor

Hello All!

Is ther a simple way to determine the voltage drop on a capacitor on a low pass filter?

Thanks

Yes, for the AC voltage. Have you looked up the theory of a low pass filter and understand the term "impedance"?

The capacitor has a reactance = Xc = 1 / 2pi FC

The formulae for capacitors and resistors in series and parallel and so forth
with sinusoidal ac signals work just like for resistors only, except using complex
numbers. A simple RC low pass filter is just a voltage divider, but the impedance
of the capacitor is 1/jwC (or 1/iwC if you're a physicist). w = 2.pi.f

Thank You All!

...but wait there's more!
Capacitive reactance calculator

dlloyd,

If, in fact, "Electricity is really just organized lightning ", and if lightning never strikes the same place twice,,,, why do i keep shocking myself?

If, in fact, "Electricity is really just organized lightning ", and if lightning never strikes the same place twice,,,, why do i keep shocking myself?

Lets test this with the transitive theory (if a=b and b=c, then a=c):

Lets define the wording:

electricity is really just organized lightning
electricity = organized lightning

unorganized lightning never strikes the same place twice
organized lightning always strikes the same place/object/person
organized lightning = shock myself

So, as per the transitive theory, if
electricity = organized lightning, and
organized lightning = shock myself, then
electricity = shock myself

Yup, it works.

Perhaps these could help, or migrate to 3.3V Arduino boards ;).

MarkT:
A simple RC low pass filter is just a voltage divider, but the impedance
of the capacitor is 1/jwC

Are you implying that it's simply arithmetic, that VX_c = Vsupply ? VR ?

It is simply "complex arithmetic".

The complex value represents amplitude and phase simultaneously, which is
why its so powerful for sinusoidal signals