the compiler is the one actually allocating the variable in SRAM (on the stack here), you are not giving an address of anything ➜ it knows it's not hardware related
if you were to define it as a pointer to somewhere in memory and pass the address then I would agree
Fair enough. Just to muddy the waters more, shall we move on to std::atomic 
something like volatile uint8_t *portPtr = &PORTB; would do
let's not hijack @DrDiettrich 's threads, we are out of topic
Agree, sorry, my last post on topic. Let's say it's complicated. See Here starting at 1:31:23.
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