weight scale load cell calibration factor

Projects Programming
1

Hello sir,
i am facing a calculation problem in order to display measured weight.
ADC output on zero weight =2230 ADC o/p at 2000gram(calibrate)=2590,
how to calibrate on 2000 and how to get measured weight???

2

Assuming a linear transfer function:
How about using the map() function?

map(2230, 2590, 0, 2000);

Map only works with integers (returns the long data type).
If you want to map with float data type, Google "arduino map floats" for lots of information.

3

The difference between 2230 and 2590 is 360. Take your reading, subtract 2230, and multiply by 2000.0/360.0 to get grams (or 2.0/360.0 to get kilograms).

4

johnwasser:
The difference between 2230 and 2590 is 360. Take your reading, subtract 2230, and multiply by 2000.0/360.0 to get grams (or 2.0/360.0 to get kilograms).

thanks for support.

5

Given:
A(w1, adc1) = A(0, 2230)
B(w2, adc2) = B(2000, 2590);
C(w, adc) //w = unknown weight to be measured, adc = adc output

Find w in terms of adc:

(2590 - 2230)/(2000 - 0) = (2590 - adc)/(2000 - w)
==> 360/2000 = (2590 - adc)/(2000 - w)
==> 9/50 = (2590 - adc)/(2000 - w)
==> 2000 - w = (2590 - adc)50/9
==> 2000 - w = 259050/9 - 50/9adc
==> w = 50/9adc + 2000 - 259050/9
==> w = 50/9adc + (2000 -2590*50/9) gm

6

thank u very much,
what for tare the weight??

7

groundFungus:
Assuming a linear transfer function:
How about using the map() function?

map(2230, 2590, 0, 2000);

Map only works with integers (returns the long data type).
If you want to map with float data type, Google "arduino map floats" for lots of information.

LC_basetools has a float mapper. And a float nonlinear mapper as well.

Just sayin..

-jim lee

8

mohitnama400:
what for tare the weight??

Use the new value instead of 2230 or remember the tare weight and subtract that from the measured weight.

9

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