If my calculations are correct, around 40 ohms yields 125 ma .6 watts. I am sure it can handle that but I guess I shouldn't use a .25 watt resister.
Is there some way to knock things down more and retain at least a one volt range to measure?
If my calculations are correct, around 40 ohms yields 125 ma .6 watts. I am sure it can handle that but I guess I shouldn't use a .25 watt resister.
Is there some way to knock things down more and retain at least a one volt range to measure?