No, that does fit in a signed long, so that’s what the compiler will go for.
That’s not necessary
When comparing a signed value with unsigned value, the compiler converts the signed value to unsigned. so you get UL automagically
No, that does fit in a signed long, so that’s what the compiler will go for.
That’s not necessary
When comparing a signed value with unsigned value, the compiler converts the signed value to unsigned. so you get UL automagically