I am just wondering how this program works with the device? Is there a simple way i could make a more simplified version (i'm new to c++) that prints the value, or position of my hand , on the serial monitor?
Here is the project website
here is the confusing code, confusing in the sense that I do not understand how it gets the position of your hand in the box.
//
// By Kyle McDonald
// From the instructables project at:
// http://www.instructables.com/id/DIY-3D-Controller/
#define resolution 8
#define mains 50 // 60: north america, japan; 50: most other places
#define refresh 2 * 1000000 / mains
void setup() {
Serial.begin(115200);
// unused pins are fairly insignificant,
// but pulled low to reduce unknown variables
for(int i = 2; i < 14; i++) {
pinMode(i, OUTPUT);
digitalWrite(i, LOW);
}
for(int i = 8; i < 11; i++)
pinMode(i, INPUT);
startTimer();
}
void loop() {
Serial.print(time(8, B00000001), DEC);
Serial.print(" ");
Serial.print(time(9, B00000010), DEC);
Serial.print(" ");
Serial.println(time(10, B00000100), DEC);
}
long time(int pin, byte mask) {
unsigned long count = 0, total = 0;
while(checkTimer() < refresh) {
// pinMode is about 6 times slower than assigning
// DDRB directly, but that pause is important
pinMode(pin, OUTPUT);
PORTB = 0;
pinMode(pin, INPUT);
while((PINB & mask) == 0)
count++;
total++;
}
startTimer();
return (count << resolution) / total;
}
extern volatile unsigned long timer0_overflow_count;
void startTimer() {
timer0_overflow_count = 0;
TCNT0 = 0;
}
unsigned long checkTimer() {
return ((timer0_overflow_count << 8) + TCNT0) << 2;
}