Dear all.
I need guideline for warm gear selection single axis tracker and dual axis tracker.
Gear train - Wikipedia gear ratio calculation
http://www.sunflowerenergyinc.com/Slewing_Drive_-_032511_-_REV.03.pdf example for worm gear box.
This seems to be a mechanical engineering question rather than an Arduino question.
But nobody will be able to help you unless you provide a lot more information about your requirements.
...R
(angular) speed ratio is same as gear ratio, and for a worm the
number of teeth means the number of helices.
torque ratio for most gear systems is the inverse of speed ratio,
less some static and dynamic friction losses.
Think power = angular velocity x torque, and power is conserved
(apart from friction losses).
However worm gears are very high friction (sliding contact), so expect
poorer performance in terms of torque boosting. They do have
the unique ability to resist back-torque completely (unless very
open multi-helix design).
They are favoured for winches and other applications where you don't
want a power-failure to allow the load to move / drop.
The box you refer to has a 24V motor and a train of two worm drives, BTW.
MarkT:
(angular) speed ratio is same as gear ratio, and for a worm the
number of teeth means the number of helices.torque ratio for most gear systems is the inverse of speed ratio,
less some static and dynamic friction losses.Think power = angular velocity x torque, and power is conserved
(apart from friction losses).However worm gears are very high friction (sliding contact), so expect
poorer performance in terms of torque boosting. They do have
the unique ability to resist back-torque completely (unless very
open multi-helix design).They are favoured for winches and other applications where you don't
want a power-failure to allow the load to move / drop.The box you refer to has a 24V motor and a train of two worm drives, BTW.
Thanks for reply
I.e means.
(No of teeth in primary)/(No of teeth in secondary)=(speed in primary)/(speed in secondary)=(torque in secondary)/(torque in primary)
if gear ratio 1:10 and speed at primary is 300 rpm.i.e means my worm gear running @ (3000 rpm).
Is there any relation ship between speed vs load , torque vs load, input and out put power consideration for worm gear box.
Worm gears are used to REDUCE the rpms! one turn of the 'worm' will make the gear rotate with 1 teeth. this means that if you have 10 teeth, and you rotate the input axis with one turn, that the output shaft will rotate with 360/10' degrees (36°).
If you add a motor with 300 rpm, the output shaft will rotate with 30 rpm.
Normally it would even be impossible to rotate the gear with the purpose of getting the smaller-worm axis to rotate. Mostly this is also very bad for the worm/gear, unless manufactured specifically for this purpose.
The torque ratio is equal to the rpm ratio. if you have a 10:1 speed reduction, your output shaft will have 10 times the torque of the input shaft. (U used 1:10, which is used to indicate higher output then input speed)
For your tracker you will need very low rotation speeds, high torque. However we can't just say you need 'that' one, because we don't know how big the tracker is, which loads there will be on the motor etc. You should atleast use some big bearings to take the forces from the motor.
Btw, I assume you want to make a solar tracker, I did this for my final school project. Turns out that small trackers are way to expensive to make. I'm guessing that those gearboxes are quiet expensive...
For your tracker you will need very low rotation speeds, high torque. However we can't just say you need 'that' one, because we don't know how big the tracker is, which loads there will be on the motor etc. You should atleast use some big bearings to take the forces from the motor.
Ya i know this required high torque and must be run @ very low speed
Only I need to input power and output power calculation .If there is system considered as 5kw-10kw what are parameter must me know to calculate input / output power.
How radial and axial load calculated?
I know bit expensive but its fine for us
I got equation like this.
(No of teeth in primary)/(No of teeth in secondary)=(speed in primary)/(speed in secondary)=(torque in secondary)/(torque in primary)
and
o/p power = (angular velocity * torque)
Well, the main load on your tracker will be the weight of the solar panels and the force caused by winds.
For my own tracker I did some calculations using wind simulations in Solidworks(CAD software):
The pressure on the panel results in a force, and u need to calculate this force to know what forces are involved.
I took 100km/h winds when the panel was in its 'worst' position to calculate mine. On one panel (2.7m²) there was a force of 1kN.
So I can imagine that a 5kW installation can catch very much wind. Say 20 panels, involves already forces of 25+kN...
The torque on the tower on which the panels are mounted will also be very large. You will need some huge bearings to compensate those forces. The other problem will be making it as light as possible, yet strong enough to cope the (unpredictable) weather...
I don't know where you are from, but unfortunately, I wrote my results in dutch. However maybe you can use google translate or something to have a look at the whole calculations (primitive tho, just so we had an idea of the choices which had to be made): http://gip-zonnevolger.be/Sterkteberekening2.html
The bearings take everything except the torque!
Specifically bearings take axial load (thrust bearings) and radial loads (standard bearings),
but let the torque through (otherwise they wouldn't be bearings!)
The worm gear itself has to hold up against the torque loads.
No no 
I think you misunderstood me, I meant it like this :
The torque on the motor will be created by winds with an angle on the solar panels and when rotating the construction to the sun.
Btw- I think we really need more information about the size of the tracker, weather involved, etc to even make an estimation of the required motor/worm gearing...