2 neopixel strands data corruption

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1

Hello everyone,
First of all this is my first post here, i'm not fully aware of the rules for posting but I'll try to organize my question the best I can.

I'm making this WS2812B watch as a project for school, I'm using the attiny414 in combination with the tinyNeoPixel library. Everything is working fine hardware-wise so I'm able to make a LED-chase following the RTC using an external oscillator. The problem arises when I try to use my second data line to blink the other 12 LEDS. Then I just get 2 solid LED's on, and the first chase working. The chase works on both lines by the way, just not at the same time...

This is the code I have

#include <tinyNeoPixel.h>
#include <avr/sleep.h>

#define D1 PIN_PA4
#define D2 PIN_PA5
#define LED_POWER PIN_PA1
#define TEST PIN_PA2

#define NUM_LEDS 12
#define BRIGHTNESS 50

byte teller = 0;
bool ledStates[NUM_LEDS] = { false };

tinyNeoPixel strip1 = tinyNeoPixel(NUM_LEDS, D1, NEO_GRB + NEO_KHZ800);
tinyNeoPixel strip2 = tinyNeoPixel(NUM_LEDS, D2, NEO_GRB + NEO_KHZ800);

#define RTC_EXAMPLE_PERIOD 511

void setup() {
  // put your setup code here, to run once:
  pinModeFast(TEST, OUTPUT);

  uint8_t temp;
  temp = CLKCTRL.XOSC32KCTRLA;
  temp &= ~CLKCTRL_ENABLE_bm;
  CPU_CCP = CCP_IOREG_gc;
  CLKCTRL.XOSC32KCTRLA = temp;

  while (CLKCTRL.MCLKSTATUS & CLKCTRL_XOSC32KS_bm) {
    ;
  }

  temp = CLKCTRL.XOSC32KCTRLA;
  temp &= ~CLKCTRL_SEL_bm;
  CPU_CCP = CCP_IOREG_gc;
  CLKCTRL.XOSC32KCTRLA = temp;  // selecteren van externe oscillator

  temp = CLKCTRL.XOSC32KCTRLA;
  temp |= CLKCTRL_ENABLE_bm;
  CPU_CCP = CCP_IOREG_gc;
  CLKCTRL.XOSC32KCTRLA = temp;  // oscillator enablen

  while (RTC.STATUS > 0) {
    ;
  }
  RTC.PER = RTC_EXAMPLE_PERIOD;
  RTC.CLKSEL = RTC_CLKSEL_TOSC32K_gc;
  RTC.CTRLA = RTC_PRESCALER_DIV32_gc | RTC_RTCEN_bm | RTC_RUNSTDBY_bm;

  cli();
  // RTC.INTCTRL |= RTC_OVF_bm;
  RTC.PITINTCTRL = RTC_PI_bm;           /* PIT Interrupt: enabled */
  RTC.PITCTRLA = RTC_PERIOD_CYC32768_gc /* RTC Clock Cycles 32768, resulting in 1Hz */
                 | RTC_PITEN_bm;        /* Enable PIT counter: enabled */
  sei();

  // // LED init
  strip1.begin();
  strip2.begin();
  strip1.setPixelColor(teller, 255, 255, 0);
  strip2.setPixelColor(teller, 255, 255, 0);
  ledStates[teller] = true;
  strip1.show();
  strip2.show();

  // Sleep init
  set_sleep_mode(SLEEP_MODE_PWR_DOWN); /* Set sleep mode to POWER DOWN mode */
  sleep_enable();                      /* Enable sleep mode, but not going to sleep yet */
}

// ISR(RTC_CNT_vect){
//   RTC.INTFLAGS = RTC_OVF_bm;
//   // PORTA.OUTTGL |= PIN2_bm; // toggle PA2 output voor test
// }

ISR(RTC_PIT_vect) {
  RTC.PITINTFLAGS = RTC_PI_bm; /* Clear interrupt flag by writing '1' (required) */
}

void loop() {
  // put your main code here, to run repeatedly:
  sleep_cpu();
  if (teller == 11) {
    strip1.setPixelColor(teller, 0, 0, 0);
    strip2.setPixelColor(teller, 0, 0, 0);
    ledStates[teller] = false;
    teller = -1;
  }
  strip1.setPixelColor(teller, 0, 0, 0);
  strip2.setPixelColor(teller, 0, 0, 0);
  ledStates[teller] = false;
  strip1.setPixelColor(++teller, 255, 255, 0);
  strip2.setPixelColor(teller, 255, 255, 0);
  ledStates[teller] = true;
  strip1.show();
  strip2.show();
}

And a picture of my watch. any help is much appreciated!

IMG_0318.HEIC
IMG_0318.HEIC3024×4032 2.6 MB

2

First observation, if you set teller = -1, then subsequently use it as an index to an array which you write anything to, where did that data get written???

1 Like
3

According to what @camsysca wrote, you must not use teller = -1 as an array index

Look ar the code:

Why the separate case for clearing the 11th element?
Is it because you need to reset the teller after end of array?
Do it an easy way:

  strip1.setPixelColor(teller, 0, 0, 0);
  strip2.setPixelColor(teller, 0, 0, 0);
  ledStates[teller] = false;
  teller++;
  if (teller > 11) { teller =0;}
4

Why use two data lines? Tie DOUT of one to DIN of the other, use one data line, and treat all the pixels as one array. You only need some "mod 12" work and your sketch is simplified.

5

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