3 wire 4-20 mA Wet sensor FDS-100

Other Hardware Sensors
1

Hi
I'm new to arduino.
I've do a connection like in photo attached.
Power supply is 12 V.
the result is 99.88% in all cases so doesn't change if I put it in the water or not.
Please help me to solve that.

the code is simple,

const int sensorPin=A0;

void setup() {
 
  Serial.begin(9600);
}
 
void loop() {
  float sensorValue = analogRead(sensorPin);
  float Result;
  
  Result = ((sensorValue-204.0)*100.0)/(1024.0-204.0);  
  if(Result>0)
  {
    Serial.print("Sensor Output:");
    Serial.print(Result); 
    Serial.println(" %");
  }
  else
  {
    Serial.println("Sensor Error");   
  }
    delay(200);         
}

Connection wet sensor.png
Connection wet sensor.png1632×642 122 KB

2

You must declare your pin as an input in the setup function :
pinMode(sensorPin, INPUT);

3

Code works.

What is the value of R-shunt. Should be 250ohm for a 5volt Arduino.
The resistor in the ground line does nothing.
If you value your analogue pin, you should add a 10k resistor between R-shunt+ and A-in.
Leo..