3 wire 4-20 mA Wet sensor FDS-100

I’m new to arduino.
I’ve do a connection like in photo attached.
Power supply is 12 V.
the result is 99.88% in all cases so doesn’t change if I put it in the water or not.
Please help me to solve that.

the code is simple,

const int sensorPin=A0;

void setup() {
void loop() {
  float sensorValue = analogRead(sensorPin);
  float Result;
  Result = ((sensorValue-204.0)*100.0)/(1024.0-204.0);  
    Serial.print("Sensor Output:");
    Serial.println(" %");
    Serial.println("Sensor Error");   

You must declare your pin as an input in the setup function : pinMode(sensorPin, INPUT);

Code works.

What is the value of R-shunt. Should be 250ohm for a 5volt Arduino. The resistor in the ground line does nothing. If you value your analogue pin, you should add a 10k resistor between R-shunt+ and A-in. Leo..