Alphabet array

I have no idea how to make an array of the alphabet that could be printed on a screen with the iht letter. Any help?

What do you know about arrays?

What is "... iht letter" ?

What are you really trying to do?

Is this homework?

You could print indexed letters of the alphabet withou using arrays

void setup() {
  Serial.begin(115200);
  for (byte index = 0; index < 26; index++) {
    Serial.print(F("letter "));
    Serial.print(index);
    Serial.print(F(" '"));
    Serial.write('a' + index);
    Serial.print(F("' '"));
    Serial.write('A' + index);
    Serial.println(F("'"));
  }
}
void loop() {}
letter 0 'a' 'A'
letter 1 'b' 'B'
letter 2 'c' 'C'
letter 3 'd' 'D'
letter 4 'e' 'E'
letter 5 'f' 'F'
letter 6 'g' 'G'
letter 7 'h' 'H'
letter 8 'i' 'I'
letter 9 'j' 'J'
letter 10 'k' 'K'
letter 11 'l' 'L'
letter 12 'm' 'M'
letter 13 'n' 'N'
letter 14 'o' 'O'
letter 15 'p' 'P'
letter 16 'q' 'Q'
letter 17 'r' 'R'
letter 18 's' 'S'
letter 19 't' 'T'
letter 20 'u' 'U'
letter 21 'v' 'V'
letter 22 'w' 'W'
letter 23 'x' 'X'
letter 24 'y' 'Y'
letter 25 'z' 'Z'

Is this what you’re looking for?

char alphabet[] = " ABCDEFGHIJKLMNOPQRSTUVWXYZ";  // First element is blank

void setup() {
  Serial.begin(9600);
  Serial.println("Enter a decimal number (1 - 26):");
}

void loop() {
  char buffer[10];
  int charsRead;
  int val;

  if (Serial.available() > 0)
  {
    charsRead = Serial.readBytesUntil('\n', buffer, sizeof(buffer) - 1);
    buffer[charsRead] = '\0';
    val = atoi(buffer);
    if (val < 1 || val > 26)
      val = 0;
    Serial.print("The ");
    Serial.print(val);
    Serial.print("th letter in the alphabet is: ");
    Serial.println(alphabet[val]);
  }
}