ascii escape code - from char*[] to Serial.write()

Projects Programming
1

Hello,

I want to do something like this:

  1. define asci escape code of cursor position - for example [20;20H in array (
char* position[] = {"\"[20;20H\"", "\"[25;25H\""};
  1. then I want to use this coordinates in Serial.write()
Serial.write(27);
Serial.write(position[0]);
  1. and then print ther something
Serial.print("Something");

What am I doing wrong? A result that I see on Putty terminal emulator is something like that 20:20H" in random position. Please help me.

2
  1. then I want to use this coordinates in Serial.write()

What is Serial.write(27) supposed to be doing?

What am I doing wrong?

Posting snippets, instead of all of your code.
Not explaining what the code ACTUALLY does.
Not explaining what you are sending the serial data to.

3

Serial.write(27); is a ESC

Ok my code is:

void setup(){
Serial.begin(9600);}

void loop(){
char* position[]={"\"[22;20H\"" , "\"[25;25H\""};
Serial.write(27);                  //this means ESC
Serial.write(position[0]);  //this should place cursor in right row and column
Serial.print("Something");
delay(2000);
}

A result on Putty is:

[22,20H" Something

Serial.write(postioion[0]) doesn't set a cursor in right place.

4 
Serial.write(postioion[0]) doesn't set a cursor in right place.

Igñoring the spelling, writing a single character isn't going to move the cursor - you need to send the whole string.

5

Igñoring the spelling, writing a single character isn't going to move the cursor - you need to send the whole string.

position[ 0 ] is a pointer. The function call is correct.

6

Oops - misread.