I'm using an Arduino Pro Mini 5V with an XBee, LM35, some LEDs and buzzer powered by a combination of the DC-DC boost converter (0.9-5V to regulated 5V) and newer version of TP4056 charger with DW01 and 8205 ic. A 3.7 V li-ion battery will be used to provide power.
So my problem is, I'm adding an ionization smoke sensor (HIS-07) and A5368CA IC for the sensor, and I don't know where to get the 9 V to power up the sensor. However, I have two ways in mind to address this.
The first is to use an adjustable voltage step-up booster instead of the DC-DC boost converter. I'll supply power to the Arduino's RAW pin instead of VCC so it can accept up to 9V.
Second case is, I'll use a voltage doubler circuit, whose input connection is parallel to Arduino's VCC and GND. This way, I can connect the circuit's output connection to the HIS-07 sensor and the IC.
Which method is more efficient, less noisy andpower hungry? I'm sorry I have no computers with me now and my phone's quite outdated.
- VOLTAGE DOUBLER Circuit (BTW, is this circuit good enough? I've seen circuits much simpler than this online)
- https://www.allegromicro.com/~/media/Files/Datasheets/A5368-Datasheet.ashx?la=en&hash=D12A0D6EEE4FCE91F5262704BFEF545C82C22C49 (A5368 Datasheet)
https://goo.gl/images/mVLekq (HIS-07 pic)
4.http://www.funnykit.co.kr/bemarket/datasheet/HIS-07.pdf (HIS07 datasheet)