Convert int to char

Using Arduino Programming Questions
#1

Hi,

I have a sensor and I receive values from it between 0 and 255. I need to convert the readings from the sensor to an array of char.

For example, if my sensor reads 97 I need this 97 reading converted to the "a" (which is the representation of 97 in the ASCII table).

I need something like:

char temp[] = convertToASCII(97);

Which would be the same as:

chart temp[] = "a";

I read a lot in Google but could not find a way to do that.

Thank you.

#2

int x = 97; char y = x;

It's just numbers. There is no "conversion" needed.

Regards, Ray L.

#3

If you just want it reinterpreted as ASCII then that's something you would do when you display it. There's no difference in how it is stored. 

int anInt = 97;   // 97 == 'a'

char aChar = anInt;

Serial.println(aChar);

will print the "a" you are looking for. When print sees char type variables, it always outputs as ASCII.

#4

97 and 'a' are two ways of writing exactly the same thing. There is no conversion needed. 97 IS 'a'.

#5 
char myString[] = {72 , 101 , 108 , 108 , 111 , 0};
Serial.println(myString);

Will print “Hello”

#6 
char string_to_send[2];
int i = 97;

string_to_send[0] = i;
string_to_send[1] = '\0'; nul to terminate the string.
#7

I think that, any time you are trying to shove 2 bytes of information (i.e., an int) into a 1 byte bucket (i.e., a char), you should explicitly cast the assignment. It helps document what you're doing:

void setup() {
  // put your setup code here, to run once:
  char myStr[20];
  
  myStr[0] = (char) 97;      // Use a cast
}

Your code didn't work because you didn't define the myStr[] array.

#8