Hi,
can any one please tell me how to convert data type long to an integer in Arduino. Quick response is appreciated
Regards,
Hema
A long is an integer.
No conversion necessary
In my case i am actually trying to compare a long value with an integer but i am not getting accurate results. can any one pl suggest some solution for it.
HemaChowdary:
In my case i am actually trying to compare a long value with an integer but i am not getting accurate results. can any one pl suggest some solution for it.
Show us your code and a "non accurate result" and we may be able to help you out.
Groove:
A long is an integer.
No conversion necessary
A integer takes 2 bytes and a long takes 4 bytes on Arduino.
Best regards
Jantje
There is a concept of casting in c programming laungage and its succedors like c++ arduino ide etc
int number=0;
long secondNumber=1234567;
If(secondNumber==(long)number)
{
True Stuff goes here
}
Else{
false stuff here
}
Morenlight on the casting stuff
its always better to cast the smaller one(with respect to memory , in our case in is smaller than long) to be casted into bigger on
Casting a variable wont change its value , it will just consider the number as of a different data type
example :
Int number =0 ;
Float secondNumber = number ; // THIS WILL GIVE ERROR
float secondNumber = (float) number ; //This will work like charm
n I hope this works too (I dun have arduino yet with me I have ordered it so idk much but I hope the following example works too:
Void setup(){
Int number = 123 ;
Serial.begin(9600);
}
Void loop()
{
Serial.println((float) number);
}
This will print "1234.000000" since it is cased to float data type , which has 6 digits of precision
Grumpy_Mike:
int() - Arduino Reference
ya I guess this ia how u cast in arduino ..
so I will rewrite my example above:
int number =0 ;
Long secondNumber=123456789;
Long convertedNumber = long(number); // the first variable number is stored in convertedNumber as a long variable..
u really got to do trial and error