Distance measurement code error resultng 0

Projects Programming
1

int trig = 9;
int echo = 6;
float distance = 0;
float value = 0;

void setup() {
pinMode (trig,OUTPUT);
pinMode (echo,INPUT);
Serial.begin(9600);
}

void loop() {
digitalWrite(trig,LOW);
delay(2);
digitalWrite(trig,HIGH);
delay(10);
digitalWrite(trig,LOW);
delay(2);
value = pulseIn(echo,HIGH);
distance = (value*0.0340/2);
Serial.println(distance);
}

What's the mistake I've done on the code it keeps on giving 0 as the result...
Thanks in advance

2

pulseIn() returns 0 if no echo was seen or if it misses the echo.

Change your "delay()" calls to "delayMicroseconds() calls.

3

Uncompiled, untested(but in code tags)

const byte trig = 9;
const byte echo = 6;

void setup() 
{
  pinMode (trig,OUTPUT);
  digitalWrite (trig,LOW);
  pinMode (echo,INPUT);
  Serial.begin(9600);
}

void loop() 
{
  digitalWrite(trig,HIGH);
  delayMicroseconds(10);
  digitalWrite(trig,LOW);

  unsigned long pulseLength = pulseIn(echo,HIGH);
  float distance = (pulseLength * 0.0340 / 2);
  Serial.println(distance); 
}
4

delaying to microseconds did the trick... thanks a lot guys :slight_smile: :slight_smile: :slight_smile: