postStr += String(deviceId);
postStr += "&message_parameter=";
postStr += String(message);
postStr += "\r\n\r\n";
there is in the ending
still sometime work and some time no
now I understand
and if I connect the sensor to GPIO3 I will not be able to "debug" it - right?
or can I ? because I don't send any data to the device using serial . just read data using the serial
I just need to use 1 GPIO ...
Thanks ,
You can use GPIO2 to debug (Serial1).
Or you could debug over the network.
how can I debug over the network\GPIO2?
what I need to change in the code? wire setting?
if I change my code to work with GPIO3 - will it work?
Thanks ,
To use GPIO2 for debugging, just use Serial1 instead of Serial.
Over the network is more involved.
can you explain howto?
what I need to change in the code?
/************
GeeksTips.com
ESP8266 Arduino Tutorial - Push notification messages example
Arduino code example
www.geekstips.com
- replace the dots with your Wi-fi credentials and
- your deviceId from pushingBox account
*/
#include <ESP8266WiFi.h>
// PushingBox scenario DeviceId code and API
String deviceId = "v124511AAZA63CAB";
const char* logServer = "api.pushingbox.com";
const char* ssid = "David";
const char* password = "123456d3e4f5";
const int GPIO2 = 2;//door sensor input [b]--->this I will change to 3[/b]
bool sending = false;
void setup() {
Serial.begin(115200);
delay(1);
// Sending a notification to your mobile phone
// function takes the message as a parameter
Serial.println("- connecting to Home Router SID: " + String(ssid));
WiFi.begin(ssid, password);
while (WiFi.status() != WL_CONNECTED) {
delay(500);
Serial.print(".");
}
Serial.println();
Serial.println("- succesfully connected");
Serial.println("IP address: ");
Serial.println(WiFi.localIP());
delay(500);
pinMode (GPIO2 , INPUT);
delay(1500);
sendNotification("Sensor is now OnLIne!!");
}
void loop()
{
if (digitalRead(GPIO2) == LOW)
{
String line = "Door1 is Close";
if (sending == false)
{
Serial.println(line);
sendNotification(line);
sending = true;
}
}
else
{
String line = "Door1 is Open";
if (sending == true)
{
Serial.println(line);
sendNotification(line);
sending = false;
}
}
}
void sendNotification(String message) {
Serial.println("starting client");
WiFiClient client;
Serial.println("- connecting to pushing server: " + String(logServer));
if (client.connect(logServer, 80)) {
Serial.println("- succesfully connected");
Serial.println(deviceId);
String postStr = "devid=";
postStr += String(deviceId);
postStr += "&message_parameter=";
postStr += String(message);
postStr += "\r\n\r\n";
Serial.println("- sending data...");
client.print("POST /pushingbox HTTP/1.1\n");
client.print("Host: api.pushingbox.com\n");
client.print("Connection: close\n");
client.print("Content-Type: application/x-www-form-urlencoded\n");
client.print("Content-Length: ");
client.print(postStr.length());
client.print("\n\n");
client.print(postStr);
Serial.println(postStr);
}
client.stop();
Serial.println("- stopping the client");
}
what else?
except the wiring of the serial to GPIO2 and not U0RXD(GPIO3)?
Thanks,
here too
client.print("POST /pushingbox HTTP/1.1\n");
client.print("Host: api.pushingbox.com\n");
client.print("Connection: close\n");
client.print("Content-Type: application/x-www-form-urlencoded\n");
client.print("Content-Length: ");
client.print(postStr.length());
client.print("\n\n");
client.print(postStr);
Serial.println(postStr);
[/quote]
look at the code again
there is
client.print("\n\n");
everywhere
where do you want to me to add?
Thanks ,
client.println("POST /pushingbox HTTP/1.1");
client.println("Host: api.pushingbox.com");
client.println("Connection: close");
client.println("Content-Type: application/x-www-form-urlencoded");
client.print("Content-Length: ");
client.println(postStr.length());
client.println();
client.println();
client.print(postStr);
\n\n is not \r\n\r\n
PieterP:
To use GPIO2 for debugging, just useSerial1instead ofSerial.
Everywhere you're using "Serial.println()" for example, just use "Serial1.println()" instead.
but I need to declare what is serail1 , no ?
No.
Please read the documentation.
sorry - my mistake
I have change it
but still not working
It work 4-5 times , but after nothing I get no notification ,
but in the serial+wiresahrk I can see he send the command , but nothing
any more ideas?
Thanks ,
david1234:
sorry - my mistake
I have change it
but still not working
It work 4-5 times , but after nothing I get no notification ,
but in the serial+wiresahrk I can see he send the command , but nothing
any more ideas?Thanks ,
read the response and print it to Serial
PieterP:
No.
Please read the documentation.
I am guessing you did not see that he wasted your time with his duplicate post.
http://forum.arduino.cc/index.php?topic=549270.0
ieee488:
I am guessing you did not see that he wasted your time with his duplicate post.
[MERGED] ESP8266 change the example WiFIClient code? - Project Guidance - Arduino Forum
I didn't, thanks for pointing it out.
@david1234: Stop wasting everyone's time by discussing the same problem across multiple threads!
this is not the same
here I had a problem with the hardware connection and setting
this problem solve thank to you -and I understand my mistake.
so thank you again for helping me here !
in other post I have a probelm sending the notification
I don't think it the same problem - therefor I open another post ......
if you think it duplicate - I will "close" this one and only response to the other one
again - I don't think it's the same problem