Exit status 1 error issues

Projects Programming
1

Trying to code 3 leds to a button and one tone buzzer. What am i doing wrong here??

const int ledPin = 13;
const int ledPin2 = 12;
const int ledPin3 = 8;
const int buzzerPin = 7;
const int buttonPin = 2;

int buttonState = 0;
void setup() {

Serial.begin(9600);

pinMode(ledPin, OUTPUT);
pinMode(ledPin2, OUTPUT);
pinMode(ledPin3, OUTPUT);
pinMode(buzzerPin, OUTPUT);
pinMode(buttonPin, INPUT);
}

void loop() {

buttonState = digitalRead(buttonPin);

if (buttonState == HIGH) {

digitalWrite(ledPin, HIGH);
digitalWrite(ledPin2, HIGH);
digitalWrite(ledPin3, HIGH);
tone(buzzerPin, 100);
Serial.println("----------------");
} else {

digitalWrite(ledPin, LOW);
digitalWrite(ledPin,2 LOW);
digitalWrite(ledPin,3 LOW);
noTone(buzzerPin);

Serial.println("ALARM DEACTIVATED");
}
}

2

Make a couple changes:

pinMode(buttonPin, INPUT_PULLUP); // turn on internal pullup resistor

Wire the button to connect the pin to Gnd when pressed.
Then change the checking logic:

if (buttonState == LOW) { // was button pressed?

3

yes.

4

still getting the same result

5

How about posting the new code and perhaps telling us what "the same result" is? I.e. actual details of any error you see.

Steve

6 
    digitalWrite(ledPin, LOW);
    digitalWrite(ledPin, 2 LOW);
    digitalWrite(ledPin, 3 LOW);

Spot the difference between the first line and the other 2