find string in char array

Projects Programming
1

Hello all!

I am going round in circles trying to determin if an output char array (from a GSM module serial) contains a certain telephone number.

I tried this with the car array "buffer" containing up to 64 chars from a GPRS.read() operation.

String aPhone1 = "07676438";
String bufferString(buffer);
int posInStr = bufferString.indexOf(aPhone1);

this does not work - so I am looking for an operation to convert "buffer" to a string bufferString, so I can use the .indexOf method.

Can anyone help?

2

beejayf:
Hello all!
Can anyone help?

With nullterminated strings (char arrays) always use the strstr() function to find a nullterminated string and its position within another nullterminated string.

3

so I am looking for an operation to convert "buffer" to a string bufferString, so I can use the .indexOf method.

Not going to help you with that. There are functions to determine if a string (a NULL terminated array of chars) contains a string. Use them, instead. ANY book on C will show all of the string handling functions, so you never need to use the String crutches again.

4

Here are the most commom functions.

5

here is an example (run it with your console set at 115200 bauds)

const char* GSMbuffer = "12345678901234567-->07676438<--1234567890";
const char* phoneNumber = "07676438";

void setup() {
  char * p;
  Serial.begin(115200);
  p = strstr (GSMbuffer, phoneNumber);
  if (p) {
    Serial.print("found ["); Serial.print(phoneNumber); Serial.print("] at position "); Serial.print((int) (p - GSMbuffer));
  } else {
    Serial.print("could not find ["); Serial.print(phoneNumber); Serial.print("]");
  }
}

void loop() {}