How can I control 3 relay module in 3 ultrasonic sensor

Can you please add bigger numbers to this so it is easy to read?
Can you please erase all unused numbers so it becomes easier to get the overview?
image

This is the reason why you should draw a

hand drawn schematic

which only contains the used IO-pins

Hi, @profcircuit05

The protoboard you are using has a break in the side power bus.
Jumper them and see if it helps.

Do you have a DMM? (Digital MultiMeter)
If so check your supply to all components on the board.

Tom... :smiley: :+1: :coffee: :australia:

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it's working... thank you very much....

Your second fancy amateur-picture is acceptable.
Still it is not professional.

This is an example how a hand-drawn schematic could look like.

It has an optimimum between fast to create and precision for temporarily use.

All the relevant information is there. All irrelevant information is left out.
It is easier to get the overview.

what becomes immidiately obvoius is:

All three relays and all ultrasonic sensors are powered from the Arduino 5V-pin.

Powering relays from the Arduino's 5V pin draws too much current.
Each realy draws minimum 5V / 100 Ohm = 50 mA.
150 mA x 3 = 150 mA.
This is to much for the onboard-voltage regulator.
This voltage-regulator will overheat and shut down.
Especcially if you supply the Arduino with 12V.

I don't know if you have a higher resolution camera. The picture you posted is barely analysable. You should post pictures with at least 2 Megapixel if possible better 8 megapixel.

Do you have a digital multimeter?

If yes measure the coil-resistance of the relays. My estimation is 100 Ohm.
And I would not be astonished if it were only 50 Ohms
=> doubling the current to 5V / 50 Ohms = 100 mA for each relay.

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I thought the 2 line for power supply are connected.
image

I can't see from that image, but a quick test with a DMM will show it.

Tom... :smiley: :+1: :coffee: :australia:

If your camera is able to adjust to a sharp picture in this small distance like shown here
image

I mean if the whole picture only shows two centimeter left / right from the middle It might be seeable.

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