How to amplify voltage drop

You have to know beforehand what the lower voltage will be, R6 will null out that voltage to zero

If it's 1V then apply a 1V voltage source to R17 and adjust R6 untill the voltage at test point T1 (output of U1) is zero. Remove the 1V voltage source and connect what you had connected to your analog read to R17.
You can later readjust R6 to give you whatever output range looks good.

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thanks, I'll test and update.

I'm going to pick a nit here Jim.
With a single rail amp he can have R6 Way Off and still read 0V at T1. Should the instruction be something like "Adjust R6 until T1 just reaches 0V" or "Adjust R6 until T1 is as close to 0V as possible" and accept that little error?

In fact pure water is a very poor conductor.

That is to be expected.You have a potential divider with R1 (water) = 1k - 1M and Radc = c 1Gohm

Hi, I was testing this, built the whole circuit, then I smelled smoke and noticed my preset was sparking.

What I did? the preset has three pins, the single lonely pin I connected to the 5V and one of the two pins I connected to GND and the second of the two pins I connected to as shown. The preset is sparking when I turn it to the extreme end to reach zero volts at T1. Why?

I'm not sure what you mean by preset. Do you mean the variable resistor R6?

Yes the variable resistor, 50K. This is what I am using. The image is of 10K but I am using 50K.
image

Connect like this
image

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The electrical resistivity of water (0.2 Ω·m sea water, 2 to 200 Ω·m drinking water, 180000 Ω·m deionized water at 20°C)

Resisitivity is NOT resistance.

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