How to make Commander accept CR+LF as line terminator

Projects Programming
1

How does one make Commander accept the 2-character sequence CR+LF (0xD+0xA) as a valid line terminator?

You can change from the default (0xA) to 0xD (or any there character, with endOfLineChar(<single_hex_val>); , but NOT BOTH 0xD, 0xA. The default on a term program my users MUST use is CR+LF.

Any advice?

2

Shouldn't be a problem..
CR is the 'usual text line terminator (the LF is added for old style terminals that needed to be pushed to the next 'line').

If you act on the CR - you can simply drop/ignore the LF - unless you are explicitly looking for them in a CRLF pair.

3

Tried that (cmd.stripCR(1)) BUT.. Since it ignores the CR, it ALSO doesn't echo it back.. So the line you just entered gets wiped out.

4

Commander contains this code which implies that it will strip out any Returns (0x0D) or Linefeeds (0x0A) that it finds after the EOF character:

		if(inByte == EOFChar && !ports.settings.bit.dataStreamMode){
			//println("EOF Found, tidying up");
			commandState.bit.dataStreamOn = false;
			//get rid of any newlines or CRs in the stream
			while(ports.inPort->peek() == '\n' || ports.inPort->peek() == '\r') ports.inPort->read();

That implies that if you are receiving 0x0D,0x0A and you set 0x0D as the EOF character, the 0x0A will be stripped for you.

5

OP, remember the CR & LF in this case are line terminators.
Both of the are irrelevant to your message.

It’s unimportant what happens to them once you know the command line has ended.

6

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