How can I turn up the voltage of a 18650 rechargeable battery from 3.7v to 6v to power an arduino board with electronic components like capacitors or regulators or whatever except with boost modules like the mt3068 (tried that already and they suck).
It is worth mentioning that I already did a search for this on the internet and on YouTube and the truth is that I cannot find something specific for this and that is why I come to ask you to share your knowledge with me. Thank you so much
Which Arduino pin did you apply 6V?
gabrielnicolau:
How can I turn up the voltage of a 18650 rechargeable battery from 3.7v to 6v to power an arduino board with electronic components like capacitors or regulators or whatever except with boost modules like the mt3068 (tried that already and they suck).
It is worth mentioning that I already did a search for this on the internet and on YouTube and the truth is that I cannot find something specific for this and that is why I come to ask you to share your knowledge with me. Thank you so much
Just have to start from the beginning ------- in steps. Mention what you did, and what issues you encountered.
Expressions like 'tried that already and they suck' is too vague. You should mention something like ----- you obtained a particular DC to DC converter boost module, and you measured the output voltage as being 'X' volt DC, and then you tested the boost module by applying suitable size (and power rating) test resistor loads -- to make sure that the boost converter works and delivers adequate power. And then ....... etc etc. State what you did, and state what issues you encountered.
The question from JCA is a good one too - as in where was the 6V applied? Which pin of the arduino?
Also, consider why was 6V was chosen for the supply voltage?
Hi,
An easy way is to use the built-in Arduino regulators, by inputting 7.2V (TWO 18650 in series) into the Arduino External Power pin.
And if you use THIS UNO-compatible version, it has built-in 5V at 2A regulator. I use this to run two DC robot motors with a modern FET motor driver from the 5V output. With the efficiency of the onboard switch-mode regulator the robot runs for a long time...
Then, there is THIS 18650 Regulator that includes charging capability.
Simple, use two 18650 batteries in series (4.3V*2=8.6V) and connect it to the barrel Jack Ext DC input or Vin. (The
5V regulator input).
(I see the last poster already suggested this)
FYI, 3.7V is NOT the working voltage of an 18650 battery, it is the UNCHARGED voltage !
The WORKING voltage is the CHARGED voltage, which is closer to 4.2V.
except with boost modules like the mt3068 (tried that already and they suck).
What's the problem?
....You can't increase total power/energy so whenever you boost the voltage, the battery has to provide more current into the converter than you get out, and that shortens battery life. For that reason I'd generally TRY to avoid a voltage-boosting power supply. I'd be more likely to consider it if the higher voltage was for a something other than the main power supply.
A step-down switching regulator does the opposite... You can get more current out of the regulator than you put-in. (Not the case with linear voltage regulators.)
.You can't increase total power/energy so whenever you boost the voltage, the battery has to provide more current into the converter than you get out, and that shortens battery life.
Simple physics. If you double the voltage , you half the current:
Example:
4000mAh battery@4.2V (Assume 1C discharge rate)
P= IV = 4A 4.2V = 16.8 W
Let V = 2*4.2V
I=P/V = 16.87W/8.4V = 2A
You could make your own bare bones Arduino and run it at 8MHz - will run at the lower voltages and suit your battery .
Such a device would give you the opportunity to sensibly use low Power /sleep options too .