Hi Everybody.
Thanks,Program Fixed
You are missing a semicolon after float tbd4.
Use code tags!
Use arrays
This is your full error message
sketch_nov22a:10: error: expected initializer before 'int'
int tempwb1 = A0;
^
C:\Users\sterretje\AppData\Local\Temp\arduino_6222604773d304ba26dd4050c57c949e\sketch_nov22a.ino: In function 'void setup()':
sketch_nov22a:24: error: expected ';' before 'pinMode'
pinMode(motor1, OUTPUT);
^
C:\Users\sterretje\AppData\Local\Temp\arduino_6222604773d304ba26dd4050c57c949e\sketch_nov22a.ino: In function 'void loop()':
sketch_nov22a:29: error: 'tempwb1' was not declared in this scope
twb1 = analogRead(tempwb1);
^
sketch_nov22a:36: error: expected ';' before numeric constant
twb4 = (5.0 * twb4 * 100.0)1024.0;
^
sketch_nov22a:43: error: 'tdb4' was not declared in this scope
tdb4 = analogRead(tempdb4);
^
sketch_nov22a:58: error: expected ';' before 'Serial'
Serial.println(tdb3);
^
sketch_nov22a:61: error: expected ';' before 'Serial'
Serial.print("tdb4= ")
^
exit status 1
expected initializer before 'int'
Usually you work through them from top to bottom.
sketch_nov22a:10: error: expected initializer before 'int'
^ ^ ^
| | |
| | +---- error
| |
| +----------------- line number
|
+--------------------------- filename
The next lines indicate where the compiler lost you; the little ^ indicates where the compiler could no longer follow your code
int tempwb1 = A0;
^
The error is (in this case) just before that; in this case because you missed a semi-colon (as mentioned above) after the declaration of tdb4. You're actually missing a few 
i found another problem. can you solve it for me?
And we have to guess what it is?
No.
I think it will be silly for your output to look like this:
twb1 =and so on.
saidhans:
Hi Everybody.
Thanks,Program Fixed
Enjoy your forum timeout.