I have a two dimensional array initialized as such
uint8_t array2dimension [x][y];
and would like to store a row into a 1 dimension array/
//store a random row into array1dimennsion
int range = x - 0 + 1;
uint8_t index = rand() % range + 0;
uint8_t array1dimension[y] = array2dimension[index];
But the code above throws an error
> array must be initialized with a brace-enclosed initializer
This is an invalid array definition/initialization statement. Declare the 1D array elsewhere.
Use memcpy, or a pointer if you don't need to copy it
Here is an example aOob36 - Online C++ Compiler & Debugging Tool - Ideone.com
array1dimension[y] = array2dimension[index];
This still throws an error though,
error: invalid array assignment
Post ALL the code, using code tags.
You need to do that with a for loop for each element in the row (or memcpy() if what you call a row is the last dimension of the array)
C++ does not copy subarays for you
If you don’t need the copy, you could get a pointer to the start of the row (array data is guaranteed to be contiguous)
Why? Will your code modify the new 1-D array while the original 2-D array MUST remain unchanged? If not just access the row you need in the original array.
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