Interrupt is not being detected by the rp2040

Projects Programming
1

So I am attempting to listen to an interrupt from a specific pin, but the function attached to the interrupt is not executing.

Could someone point out what im doing wrong? Im using a rp2040 raspberry pi pico board using the latest core by Earle E Philhower V2.2.0

bool pressEvent = false;
const int interruptPin = 9;

void switchPressed() {
  pressEvent = true;
}

void setup() {
  Serial.begin(9600);
  while (!Serial);
  Serial.println("Starting");

  pinMode(interruptPin, INPUT);

  Serial.println("Listening to touchpad");
  attachInterrupt(digitalPinToInterrupt(interruptPin), switchPressed, RISING);

}

void loop() {
  // put your main code here, to run repeatedly:
  Serial.print(digitalRead(interruptPin));
  Serial.print("\t");
  Serial.println(pressEvent);

}

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As you can see in the serial monitor the print for pressEvent remains 0 even though digitalRead sees a logic high. The signal is there, so it would seem to point that im doing something wrong with my code?

2

Try declaring pressEvent as volatile.
BTW, you never set it false again.

3

declaring it volatile sadly did not solve it :frowning:

volatile bool pressEvent = false;

I intentionally did not set it to false so that i can clearly see if the ISR was executed. This is only a simplified code anyway to demonstrate my problem

4

HackadayU course #2 is on interrupts: you may find some jewels.

5

Something is wrong with the core, rolled back to v1.13.0 it works... will be posting on earl's github

1 Like
6

Thanks for posting the update

7

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