I have a sketch here that calculates the mean value of A0. Now I want to do the same thing for A1 in parallel and separately in the program. Unfortunately, it's not that easy to do. Does anyone have any ideas? float puffer; void setup() { Serial.begin(9600); } void loop() { int sensor = analo…

[image] thomas1189: Unfortunately, it's not that easy to do. You will have to explain why your statement above is true. Why that should be so it not immediately obvious.

you can't just copy the routine for A0 and run it for A1 ( copy and past in the same way for A1) it must be possible to do the same for the analog input A1

What do you mean by "copy the routine"? You seem to be making things very difficult for yourself. I was able to add the calculations for A1 with 4 lines of code in loop() in less than a minute. float puffer1,puffer2; void setup() { Serial.begin(9600); } void loop() { int sensor1 = analogRead…

In addition to cut and paste, you would change A0 to A1, and define a new global variable, perhaps "puffer1" for mittelwert() to use. Doesn't seem too difficult.

Also, you can change the pin you read... using the same formulae. addOne = !addOne; // 0 then 1 then 0... sensor = analogRead(14 + addOne); // A0 = DIO14 spannung = sensor * (5.0 / 1023.0) * 6; mwert = mittelwert(spannung, puffer, 10); Serial.println(mwert);

[image] xfpd: addOne = !addOne; // 0 then 1 then 0... sensor = analogRead(14 + addOne); // A0 = DIO14 spannung = sensor * (5.0 / 1023.0) * 6; mwert = mittelwert(spannung, puffer, 10); Serial.println(mwert); I would prefer: float mwert, spannung; float puffer[] = { 0, 0 }; cons…

Value from A0 and A1 must be separately, in this case values from A0 and A1 mixed, right?

Your question was already answered in your other thread: [image] Mittelwert mit float Deutsch Habe hier einen Sketch mit dem man einen Mittelwert von A0 berechnen kann. Nun möchte ich das parallel und separat im Programm auch für A1 machen. Nur leider geht es nicht so oh…

What your code is calculating is not a mean value. It is more correctly called an "exponentially smoothed" value. You can read about what that is here: Exponential smoothing - Wikipedia In the case of your code, the variable called faktor is 1/alpha in the discussion above, and the formula is rear…

[image] thomas1189: A0 and A1 must be separately In post #7 and post #6, A0 and A1 are read separately. [EDIT] see post #13

Mean value calculation in parallel A0 and A1

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grb June 8, 2025, 6:50pm 9

Your question was already answered in your other thread:

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Mean value calculation in parallel A0 and A1

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