Need help with Decrement Coding

Hi,
Does anyone knows how to make a decrement code without it having showing negative values or the value that show on LCD goes beyond 2 digit?

The problem that I’m facing is…after it goes below -1 and I start to +1 it back…the value started to +10 due to the symbol “-” shown before.

I attached my coding in case if you can point out anything wrong in the code…

thanks in advance

Counting_Cust.ino (1.24 KB)

#include <CapacitiveSensor.h>

byte incrementButton = A0;
byte decrementButton = A1;

#include <LiquidCrystal.h>

const int rs = 12,en = 11,d4 = 5,d5 =4,d6 = 3,d7 = 2;
LiquidCrystal lcd(rs, en, d4 ,d5, d6, d7);

int switchPin = A0;
int switchPin1 = A1;
int incrementState = 0;
int lastIncrementState = 0;
int decrementState = 0;
int lastDecrementState = 0;
int counter = 0;
int val = 0;

void setup() 
{
  pinMode(switchPin, INPUT);
  pinMode(switchPin, INPUT);
  lcd.begin(16, 2);
  lcd.print("No. Cust.");
}

void loop() 
{
  if(val = analogRead(switchPin));{
    if(val == HIGH);{
      incrementState = 0;
    }
  }
  if(val == LOW);
  else{
    incrementState = 1;
  }
  if(incrementState == HIGH){
    counter = counter + 10;
    lcd.setCursor(12, 1);
    lcd.print(counter);
    delay(1000);
  }
  {
    if(val = analogRead(switchPin1));{
      if(val == HIGH);{
        decrementState = 0;
      }
      if(val == LOW);
      else{
        decrementState = 1;
      }
    }
    if(decrementState == HIGH){
      counter = counter -10;
      lcd.setCursor(12, 1);
      lcd.print(counter);
      delay(1000);
    }
  }
  lastIncrementState = incrementState;
  lastDecrementState = decrementState;
}
  pinMode(switchPin, INPUT);
  pinMode(switchPin, INPUT);

You only need to do it once.

 if(val = analogRead(switchPin));{
    if(val == HIGH);

Triple Oops.
Lose the semicolons, do a digitalRead

if(val == LOW); Again, lose the semicolon.
Or just use “else”