My code:
#include <EEPROM.h>
int zz;
int EEsize = 1024; // size in bytes of your board's EEPROM
int pass[4] = {1,2,3,4};
int pass1[5] = {7,8,9,10,11};
void setup()
{
Serial.begin(9600);
}
void loop()
{
Serial.println("Writing random numbers...");
for (int i = 0; i < 4; i++)
{
EEPROM.write(i, pass[i]);
}
for(int j=0;j <5; j++ )
{
for(int k =4; k<9; k++)
{
EEPROM.write(k,pass1[j]);
}
}
Serial.println();
for (int a=0; a<EEsize; a++)
{
zz = EEPROM.read(a);
Serial.print("EEPROM position: ");
Serial.print(a);
Serial.print(" contains ");
Serial.println(zz);
delay(2500);
}
}
I am using this code to enter 2 different passwords into the locations of EEPROM so that they can be retrieved from the memory by another sketch which checks the password and decided whether the door has to be locked or not. The 1st array is getting updated, but only the last element of 2nd array is getting stored in the memory. Sorry, if it is a silly programming mistake.
Please help me with this. I am attaching a screenshot of the serial monitor output.
Thanks in advance.
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for (int j = 0; j < 5; j++ )
{
for (int k = 4; k < 9; k++)
{
EEPROM.write(k, pass1[j]);
}
}
Why the nested for loops ?
for (int j = 0; j < 5; j++ )
{
EEPROM.write(j + 4, pass1[j]);
}
Why are the arrays ints when the maximum value that they hold is 255 ?
PaulS:
It's a kind of top.
http://www.zztop.com/
I didn't know that. Come to think of it, I probably still won't know it in a couple of hours from now.
void loop()
{
Serial.println("Writing random numbers...");
for (int i = 0; i < 4; i++)
{
EEPROM.write(i, pass[i]);
}
You are going to wear out your EEPROM really quickly doing that. I suggest putting the writes into setup, not loop.