Not able to print the entire string

[SuperM]

Hello,

I'm reading a QR code and printing the string from it in the serial monitor but the string is not complete for some reason, my code is the following:

#include <SoftwareSerial.h>
SoftwareSerial mySerial(3, 4); 
 
void setup()
{
  Serial.begin(9600);  
  mySerial.begin(9600); 
}
 
void loop()
{
  if (mySerial.available()) 
  {
 
    while (mySerial.available()) 
    {
      char input = mySerial.read(); 
      Serial.print(input); 
 
      delay(5);
    }
    Serial.println();
  }
}

My output is the following:
A:500829993*B:251385507*C:PT*D:FS*E:N*F:20220816*G:FS 08710022201010618/026208*021I4:*31Q06

And the correct one should be: A:500829993*B:251385507*C:PT*D:FS*E:N*F:20220816*G:FS 08710022201010618/026208*H:0-026208*I1:PT*I7:1.46*I8:0.33*N:0.33*O:1.79*Q:VDX0*R:369

I get the correct value if I just use the following code:

void loop()
{
   if (mySerial.available()) {
    Serial.write(mySerial.read());
  }
}

The thing is that I would like to store the entire string in order to print it later in the code.

[jremington]

@SuperM

delay(5);

Get rid of this completely useless delay. It results in the serial input buffer being overrun.

To store a string, accumulate it in a zero-terminated character array (C-string). For the details, see the Serial Input Basics tutorial.

[red_car]

At 9600 baud, you will receive a character about every 1ms.

Your delay means you only read a character every 5ms.

The serial buffer is 64 bytes... so as @jremington has said you will quickly fill it up and then data is lost.

Use a char array to hold the data and read it as it comes in.

char myData[256];
uint8_t idx = 0;
. . .
myData[idx++] = Serial.read();

[J-M-L]

I would suggest to study Serial Input Basics to understand how to deal with an asynchronous data input

[killzone_kid]

@SuperM

delay(5);

Why???