theloverosos:
actually i don't find and searched many times and didn't found
Then you need to contact the manufacturer and ask for a user manual, I'd say. Find their website and maybe they have a link for documentation. On the other hand it might be some kind of proprietary scheme where you need to buy a decoder from them, or sign a licence to get the data info. But if I were you I'd start by contacting the manufacturer.
Of course, you might be lucky and find that someone here has used that exact sensor.
it had 4 wire because it control and give aread in the same time so if any one give me an help to write code and i will try the yellow and green as a data connection but i am in need to the code
Pressure sensors such as this one often contain 4 resistors in a Wheatstone bridge arrangement.
You supply an excitation voltage across two pins, and the other two pins are outputs, which are at roughly half the supply voltage.
When you apply pressure, the voltage on one output increases slightly, whilst the other one decreases slightly
This change in voltage is usually quite small, maybe only a few millivolts.
The output is usually ratiometric, that is if you double the supply voltage then you double the output voltage. The excitation voltage is commonly 5V to 10V.
You use a circuit called an instrumentation amplifier to amplify the difference between the two outputs and and remove the offset.
You can construct an instrumentation amplifier from 3 op amps, (use 3/4 of a quad op amp for convenience) or buy a dedicated IC, such as the INA125.
My guess is that the red and black wires are the positive and ground of the excitation voltage, and that the yellow and green are the two outputs.
you are correct in the devide if the 4 wires red and black are source input and the outher signal output but how i connect it with arduino give me your advice because i am new in arduino world
need arduino code and wiring diagram
when i connect now the black and red to 5v source it gives me in the other yellow and green .017.5mv
but how i connect it to arduino to give me the actual read and can i use one wire in signal from the yellow or the green to take reads into arduino
i found out that the signal is MV when i connect red and black with 5v arduino it gaves me in the yellow and green 16.5mv so how can i connect it with arduino and what the code can run this procedure
now i try to connect yellow and green as +ve at pin a0 and -ve at pin a1 and it works kan anyone can give me a code to can actual psi pressure the difference between the both now in no pressure between 2 to 4 unitless
so i want help in that
Without knowing millivolts-per-megapascal it is impossible to do what you want. The manufacturer's datasheet can tell you. Or you experiment with known pressures and take readings at each different pressure.
While it is fun to play with old salvage equipment, if I actually want to know a pressure, I will buy a new sensor that has a datasheet. I will buy it from a reputable retailer that has stock so that next time I want to buy the same sensor I don't have to find their eBay listing again.
if you want to reverse engineer the circuit to use this sensor, then you would be well served to study about the Wheatstone bridge and how this sensor might work as JohnLincoln posted.
links from post#5 in this thread help you figure out that this device is only part of the whole circuit.
As BJHenry said, this is a re-labeled part, it is not a part number from the manufacture. Graco may have had them make the thread fitting to fit their machines, or just put their part number on an off-the-shelf part.
but, I do not follow exactly. You say you have to use that exact part. It follows that you need to plug that into the Graco circuit and there is no Arudino needed.
if you want to use an Arduino, then any sensor that is rated for 5,000 PSI can be used.
And in fact, you might destroy this part by connecting the wrong wires.
and as MorganS pointed out, you might need to get a second sensor, so that you can use one to calibrate the other.
there are dead weight testers for these high pressures, but it would seem rather extreme to go that far.