Random delay for blinking LED giving an error

Projects Programming
1

Ok so I am just starting up with this whole thing and I figured that randomizing the delay on a blinking LED would be fairly simple but I keep getting an error message that reads

"/tmp/768476775/sketch_jul6a/sketch_jul6a.ino:14:9: error: expected ';' before 'break'

delay break; // wait for a second

^~~~~

exit status 1"

Ii says that there is a ";" in front of the variable where it shouldn't be but I couldn't figure it ut after twiddling with it for a while so I figured I'd ask here.
Code:

// the setup function runs once when you press reset or power the board
void setup() {
  // initialize digital pin LED_BUILTIN as an output.
  pinMode(LED_BUILTIN, OUTPUT);
  int break = long random(0,1000);
}

// the loop function runs over and over again forever
void loop() {
  int break = long random(0,10000);
  digitalWrite(LED_BUILTIN, HIGH);   // turn the LED on (HIGH is the voltage level)
  delay break;                       // wait for a second
  digitalWrite(LED_BUILTIN, LOW);    // turn the LED off by making the voltage LOW
  delay break;                       // wait for a second
}

Hope I'm not missing anything too obvious, Thanks in advance.

2

break is a keyword and you are trying to use it as a variable. Change that to something else like dly for instance.

delay requires a number or variable inside parenthesis. Example delay(dly);

That should allow you to make progress.

3

Ii says that there is a ";" in front of the variable where it shouldn't be

No.

It says that a ";" was expected. That means that the compiler "thought" that there should be a ";" but it was missing. That was a result of getting the compiler really confused.

Just follow the advice that was given by PickyBiker to rename your variable and to use parentheses and you will get going again.

4

Thanks, I ended up getting rid of the variable since it was throwing another error, but your advice did fix the original problem.