It says:
5V 8-Channel Relay interface board, and each one needs 15-20mA Driver Current
But that doesnt account for the max 40mA per pin and 200mA all pins rule, as the Inputs only deal with the small current amounts of that opto led, right?
So whats the limit for the amount of relays and current? 300mA USB can give to the arduino? Or if i power the ardui via powerjack with 9V max 500mA, would be 500mA the limit or even more, like 1A of a 7805?
edit: or should my question be, how much current can the powerregulator of the ardui handle? cant find something in the "hardware section"
and is this true: if i use powerjack with 12V i get 12V at the VINpin of the ardu, which i could use to power up something else like a 12V relay?
In answer to the basic question, relay data sheets for that type of relay suggests somewhere around 0.4 watts to drive the relay coil. Considering that you have bought the 5 volt version, that implies each relay will require around 80mA to drive it. (0.4/5), times 8 for all relays being energised, equals 640mA at least. That being the case, and presuming you want to use this board, I'd suggest you couple a 5 volt regulator (with heatsink - it will get hot since it will be required to dissipate around 5 watts) to say a 12 volt supply and feed the relay board power from this source.
thank you, so i was right to ask first instead of just trieng it :-)
Whats this:
"5V 8-Channel Relay interface board, and each one needs 15-20mA Driver Current" about?
As i know opto LEDs need something like 1-5mA to work properly, and also that mini green LED, but not 15-20mA? Or did they mean a relay would need 20mA instead of 80mA?
I have another question:
i have a powersource that can switch between 12;9;7,5; and 6V.
and these specs:
Power: DC 9W
Current: DC 500mA
so i guess those 500mA wont be enough if i need 600mA+
But is 500mA really the limit? As using 7,5V would be 9W/7,5V = 1,2A and not 500mA, or is it meant in a different way?
"5V 8-Channel Relay interface board, and each one needs 15-20mA Driver Current" about
A lot of opto couplers need bright LEDs to transfer the current over, it is the normal sort of current.
But is 500mA really the limit? As using 7,5V would be 9W/7,5V = 1,2A and not 500mA, or is it meant in a different way?
Yes it is because with a linear regulator the current is common. So 500mA from the supply is needed to give 500mA in the load, the excess power is wasted as heat in the regulator.
Those sort of calculations only apply if you are using switching mode DC to DC converters and then you throw in an 80% efficiency term as well.