return a variable of a function

Using Arduino Programming Questions
1

hey all, i have function1() that retrun some variable let say int A , and i would like to use it in a seconde function : function2() ;, how can i do that please ?

int function1() {
int A;
return A

}

void function2() {
function1();
Serial.print(A)

}

Thnaks

2

The reference A does not exist outside function1() (read about variable scope)

You coud do:

void function2() {
  Serial.print(function1());
}

or if you need the value for something else than printing, then create a local variable to store the result

void function2() {
  int result = function1();
  Serial.print(result);
  if (result == 5) { ... }
}
3

Thank you but my function is mpore complicated it was just for explaining.

and i would to use the variabe in a condition or a boucle not just for printf ^^ , any suggestions ?

4

was editing as you typed back - read again

5

how can i do that please ?

Change function2() to accept a parameter so that you can pass a value to it, then

//either
int aVariable = function1();
function2(aVariable);

//or

function2(function1());


int function1()
{
  int A;
  return A
}

void function2(int aParameter)
{
  function1();
  Serial.print(aParameter)
}
6

It’s still the same. Just imagine that your function call magically gets replaced by that return value.

So in an if statement:

if(function1() == 7)