Rewrite an array with for

Using Arduino Programming Questions
1 
float y[11] = {1, 0.95, 0.85, 0.76, 0.71, 0.65, 0.52, 0.43, 0.32, 0.22, 0.11};

void setup(){
 Serial.begin(9600);
 delay(200);

 for(int i=0; i<11; i++){
  y[i]=-log10(y[i]/y[0]);
  Serial.println(y[i]);
 }

I'm trying to rewrite the y[i] using for but isnt working, how can I do this properly?

2

Your code is incomplete.

3

Full code:

// EXEMPLO - http://en.wikipedia.org/wiki/Simple_linear_regression

float x[11] = {0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1};
float y[11] = {1, 0.95, 0.85, 0.76, 0.71, 0.65, 0.52, 0.43, 0.32, 0.22, 0.11};
float lrCoef[2] = {0, 0};

// INICIANDO AS VARIÁVEIS
float sum_x = 0;
float sum_y = 0;
float sum_xy = 0;
float sum_xx = 0;

void setup(){
 Serial.begin(9600);
 delay(200);

 for(int i=0; i<11; i++){
  y[i]=-log10(y[i]/y[0]);
  Serial.println(y[i]);
 }
 
 // CHAMA O ALGORITMO DE REGRESSÃO LINEAR
 simpLinReg(x, y, lrCoef, 11);
 Serial.println("Equação Linear:");
 Serial.println("");
 Serial.print("Abs = ");
 Serial.print(lrCoef[0], 11);

 if (lrCoef[1] > 0){
  Serial.print("*Conc + ");
 }
 else{
  Serial.print("*Conc ");
 }
 
 Serial.println(lrCoef[1], 4);
}

void loop(){
}

void simpLinReg(float* x, float* y, float* lrCoef, int n){
 // CALCULOS PARA REGRESSÃO LINEAR
 for (int i=0; i<n; i++){
  sum_x += x[i];
  sum_y += y[i];
  sum_xy = sum_xy+x[i]*y[i];
  sum_xx = sum_xx+x[i]*x[i];
 }
 lrCoef[0]=(n*sum_xy-sum_x*sum_y)/(n*sum_xx-sum_x*sum_x);
 lrCoef[1]=(sum_y/n)-((lrCoef[0]*sum_x)/n);
}
4

Tells us nothing, except that you are unhappy.

What did you expect to happen and what happens instead?

5

The problem is with this part of the code

 for(int i=0; i<11; i++){
  y[i]=-log10(y[i]/y[0]);
  Serial.println(y[i]);
 }

When I run the code with this for this happens

image
image1382×879 42 KB

But if I remove the for all works well. What I'm trying to do is to convert the y[i] for y[i]=-log10(y[i]/y[0]). But I think the problem is with the y[0] that I want to fix in this line code

7

The first entry you replace is y[0]. Perhaps you should save that value first:

  float y0 = y[0];
  for(int i=0; I < 11; i++)
  {
    y[i] = -log10(y[i]] / y0);
    Serial.println(y[i]);
  }
1 Like
8

What is log10(1), and what happens when you divide any nnumber by log10(1)?

9

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