[SOLVED] #ifdef

Projects Programming
1

Hi, I cannot said hy this funtion cannot work in the first ifdef! can you help me pls?

void debugShow( String debugSwitch, String fonction, String texte){
  #ifdef debugSwitch
    Serial.println("Fonction: " + fonction + " - " + texte); 
  #else 
    #ifdef debug
      Serial.println("debugSwitch non déclaré: " + debugSwitch);
    #endif
  #endif
}
2

Hi, I cannot said hy this funtion cannot work in the first ifdef! can you help me pls?

No, sorry, I can't even understand you.

You need to post ALL of your code.

3

i found my peoblem! unfrontally. i cannot test the first srting variable because this is one compiler instruction ! i've replaced by this and it works now:

void debugShow( String debugSwitch, String fonction, String texte){

  #ifdef debugPrint
    if(debugSwitch == "debugPrint"){Serial.println("Fonction: " + fonction + " - " + texte); }
    #endif

  #ifdef debugBoutons
    if(debugSwitch == "debugBoutons"){Serial.println("Fonction: " + fonction + " - " + texte);  }
    #endif

  #ifdef debugPir
    if(debugSwitch == "debugPir"){Serial.println("Fonction: " + fonction + " - " + texte);  }
    #endif

  #ifdef debugDisplay
    if(debugSwitch == "debugDisplay"){Serial.println("Fonction: " + fonction + " - " + texte);  }
    #endif

  #ifdef debugAtmo
    if(debugSwitch == "debugAtmo"){Serial.println("Fonction: " + fonction + " - " + texte);  }
    #endif
    
  #ifdef debugRelay
    if(debugSwitch == "debugRelay"){Serial.println("Fonction: " + fonction + " - " + texte);  }
    #endif
 
  #ifdef debug
      if(debugSwitch == "debug"){Serial.println("debugSwitch non déclaré: " + debugSwitch); }
    #endif
}

thank you

4

The value in debugSwitch is NOT known at compile time. The names that ifdef sees AT COMPILE TIME must have values that are known AT COMPILE TIME.

You are completely misusing ifdef.

5

PaulS:
You are completely misusing ifdef.

Yes is right but it works fine now!

Have you another way to make the same?