Split a number 0-999 into its ones tens and hundreds digit

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1

how could i split a number 0-999 into its ones tens and hundreds digit?
the code i have now is not working correctly

speedCount = 888;
  hundreds = speedCount / 100;
  tens = speedCount / 10;
  ones = speedCount % 10;

it is making 888 into
ones: 8
tens: 88
hundreds: 8

it should be
ones: 8
tens: 8
hundreds: 8

What is a simple way i can turn a three number into its digits?

2

Take a look at Arduino/reference, math, operators..! It's a great toolbox!Don't miss the modulo operator %!

3

Integer division by 10 and 100 are among the possibilities, along with subtraction.

Hint: so is the "%" integer remainder operator.

4

you can also subtract the result of the preceding calculation from spedcount for tens and units to correct this problem..

5
Expression Result
1234 % 10000 1234
1234 % 1000 234
1234 % 100 34
1234 % 10 4
Look at first digit of each result ā†‘
6

tens = (speedCount / 10) % 10 ;

7

Assume that you have the number 789 and you want to extract these factors 7 (0x07), 8 (0x08), and 9 (0x09).

int myNum = 789;  //D2D1D0
byte D0 = myNum%10;  //D0 = 09
Serial.println(D0, DEC);   //shows: 9

myNum = myNum/10;  //myNum = 78
byte D1 = myNum%10;  //D1 = 08
Serial.println(D1, DEC);  //shows: 8

myNum = myNum/10;  //myNum = 7
byte D2 = myNum%10;  //D2 = 07
Serial.println(D2, DEC);   //shows: 7

Or

byte myFactor[3];  //array to hold positional factors of 789
int myNum = 789;

for(int i = 0; i < 3 ; i++)
{
     myFactor[i] = myNum%10;  //myFactor[0] = 0x09 ==> 9
     myNum = myNum/10;
}
8

This is for 4 digits, the logic is the same for three digits.

uint16_t value = 9876;
uint8_t  thousands;
uint8_t  hundreds;
uint8_t  tens;
uint8_t  ones;

thousands = value/1000;
hundreds  = (value/100) % 10;
tens      = (value/ 10) % 10;
ones      = value % 10;

for example, for value equal to: 0, 1, 9, 56, 70, 289, 2386, 9999:

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