Looking at Raw IR decoder sketch, I see these 2 declaration lines:
uint16_t pulses[100] [2];
uint8_t currentpulse = 0;
What is the definition of uint?
What is the _t?
What do the 8 and 16 refer to, bits, bytes, ?
Bob
Unsigned integer, either 8 or 16 bits.
uint8_t and uint16_t are C/C++ data types.
They are declared for the AVR as:
typedef unsigned char uint8_t;
typedef unsigned int uint16_t;
They are declared in stdint.h which is supplied with the compiler.
These typedefs are essentially aliases.
This allows you to use uint8_t rather than unsigned char
and uint16_t instead of unsigned int
The 8, 16 or the _t are not special in themselves as the typedef is for the full name.
By convention, many typedefs use _t in their name.
These declarations can vary depending on the processor but they are declared
such that uint8_t will give you and unsigned 8 bit value and uint16_t will give
you a 16 bit value.
The value of these is for multi byte values.
For example, the uint16_t will always give you a 16 bit unsigned value
where as unsigned int, might give you a 16 bit value or a 32 bit value depending
on the processor.
One of things that these types do not solve is endian.
The endian of the value is based on the processor type.
So a uint16_t on an AVR or intel processor is a little endian value but on a motorola processor it will
be a big endian value.
--- bill
Try stdint.h.
"_t" signifies that it is a type.