Hi all. Need some advice. I need a voltage divider to bring 5v down to 3.33v but i only have 1kOhm resistors. i need x1 1kOhm and x1 2kOhm. i was wondering if i could just twist 2 1kOhm's together to get 2k? or am i over thinking this. Oh, i need this for the logic on my bluetooth module.
Best Regards
Dave.
Yes you can.
Thank you guys.
Your r1 and r2 are different than mine. The calculator i used said to use 1000ohm and 2000ohm. If definitely dont have any 500 ohm resistors
The ratio is more important.
Do you have a multimeter?
Yeah. I just bought a new one
Take 2 1ks and set them next to each other so the actual resistors are touching.
This is parallel.
Twist the leads together.
Turn your meter to resistance Ω and measure the resistance across the pair.
A 500 ohm resistor is just two 1K twisted in parallel.
C
You also need to know how much current the device draws. To ensure that your bridge provides the correct voltage and enough current.
This is going to be for a bluetooth module. But im unsure which to buy. Theres so many on amazon.co uk. And i dont have much cash left lol
You'll need to look at them and decide which one has the right price and features, then check the datasheet for it.
You have another thread going for the selection, I think.
I do yes. So ill just see what they suggest
Cool.
Come back here after you've looked at the datasheet.
I'm pretty sure that the current across the bridge is factored out of the sum of the voltages, so:
I = V / (r1 + r2)
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