Hi all, i´m trying to make a switch for current voltage with a relay.
For first, i was doing it to switch on a LED (better to start with the basics) I bought 2 relays, one 5V and other 12V to test them.
All the references I saw on the internet, forums, fritzing and everywhere, those relays are different from mine, in pin numbers and position, so really I dont figure how to wire it; these have 5 pins
You must use a transistor (or MOSFET) to switch a relay, and you must have a free=wheel diode
to prevent the inductive kickback from destroying your transistor and Arduino.
The Arduino playground explains how to do this.
The diagram you post shows how the relay is wired internally, but you can always check with a
multimeter.
I cannot quite imagine how you could "burn" a relay - at least with Arduino-style voltages. You really should however, explain what sort of LED you are working with.
Damaging the Arduino is more of a concern.
Your diagram probably matches the connections of your relays, but is not entirely conclusive. use your multimeter on the "ohms" range to measure the resistance across the coil terminals - if it is less than 330 ohms, it is not suitable for direct drive from the Arduino (nor of course is the 12V one). The meter will also tell you which two contacts are normally closed. Connecting your 5V or 12V to the coil will then allow you to determine which are normally open.
Do you not have a multimeter? If not, that is your most important immediate acquisition. You can use a LED and a 330 ohm resistor to "suss out" the coil and the NC contacts.