hello,
is this:
char msg[64];
msg[0] = '\0';
the same as
char msg[64] = "";
?
I want to null terminate my char declaration (msg
) before I start concatenating other chars into it.
Thanks
hello,
is this:
char msg[64];
msg[0] = '\0';
the same as
char msg[64] = "";
?
I want to null terminate my char declaration (msg
) before I start concatenating other chars into it.
Thanks
Yes, those two are functionally identical.
Note that if msg
is an automatic variable (i.e., a non-static
local variable), it will not be filled with zeroes in the first case. Only the first char
will have a value of zero (after the msg[0] = '\0';
statement). In the second case, the compiler will fill the entire array with zeroes.
Whether this matters to your application is up to you.
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