Expected initializer before 'if'

I’m new to programming and I’m not sure what is causing the problem. This was meant to be a reaction time tester.

I keep getting the following errors when I compile:

ReactionTime3___Sound.ino: In function 'void loop()':
ReactionTime3___Sound:50: error: expected initializer before 'if'
ReactionTime3___Sound:132: error: expected `}' at end of input

The line highlighted when I compile is on the left parenthesis:

if(potPlayers == 1)

Here is my Auto Formatted Code:

long randNumber;
int inputPin = 3;  // create a switch input
int inputPin2 = 5; //switch input 2
int ledPin = 2;  // create output pin for LED
int ledPin2 = 4; //input pin for LED2
int potPin = A1; //create potentiometer input

const int buzzer = 9;
const int songLength = 18; //change later
char notes[] = "cdfda ag cdfdg gf "; //change later (space = rest)
int beats[] = {
  1,1,1,1,1,1,4,4,2,1,1,1,1,1,1,4,4,2}; //change later
int tempo = 150;

void setup()
{
  Serial.begin(9600);
  pinMode(ledPin, OUTPUT);         // declare LED as output
  pinMode(ledPin2, OUTPUT);
  pinMode(inputPin, INPUT);        // declare pushbutton as input
  digitalWrite(inputPin,LOW);     // enable pull-up resistors
  pinMode(inputPin2, INPUT);
  digitalWrite(inputPin2, LOW);

  pinMode(buzzer, OUTPUT);
}

void loop()
{
  int pot = analogRead(potPin);
  int potPlayers = ((int)(pot / 1023)+1);


  // Serial.print("Potent value: ");
  //Serial.println(pot);
  Serial.print("Players: ");
  Serial.println(potPlayers);

  long randDelay = random(1000);
  int state = 1;
  int state2 = 1;
  long count = 0;  //counter for player 1
  long count2 = 0; //counter for player 2
  delay(randDelay);
  int frequency(char note)

    //digitalWrite(ledPin, HIGH);
    //digitalWrite(ledPin2, HIGH);

    if(potPlayers == 1)
    {
      while(state == 1)
      {
        int val = digitalRead(inputPin);  // read input value
        if (val == HIGH)                       // check if the switch is pressed
        {
          digitalWrite(ledPin, LOW); // turn LED off if switch is pressed
          state = 0;
        }
        else
        {
          count++;
          delay(1);
        }
      }
      Serial.println(count);
    }

    else
    {
      while(state == 1)
      {
        int val = digitalRead(inputPin); //read input value
        int val2 = digitalRead(inputPin2); //read input value for pin2
        if(val == HIGH || val2 == HIGH)
        {
          if(val == HIGH)
          {
            digitalWrite(ledPin, LOW);
            Serial.println("Yellow wins!");
          }
          else if(val2 == HIGH)
          {
            digitalWrite(ledPin2, LOW);
            Serial.println("Red wins!");
          }
          int i, duration;
          for(i = 0; i < songLength; i++) //step through song 
          {
            duration = beats[i] * tempo; //length of note/rest in ms

            if(notes[i] == ' ')
            {
              delay(duration);
            }
            else
            {
              tone(buzzer, frequency(notes[i]), duration);
              delay(duration);        //wait for tone to finish
            }
            delay(tempo/10); //pause between notes
          }

          state = 0;
        }
      }

    }
  int frequency(char note)

    //returns frequency that corresponds with the note
    int i; 
  const int numNotes = 8; //number of notes stored

  char names[] = {
    'c', 'd', 'e', 'f', 'g', 'a', 'b', 'C'        };
  int frequencies[] = {
    262, 294, 330, 349, 392, 440, 494, 523        };
  //Search through the letter, and if found, return the frequency
  for(i = 0; i < numNotes; i++)    //step through notes
  {
    if(names[i] == note)    //check if it equals the note
    {
      return(frequencies[i]);    //return the frequency
    }
  }
  return(0); //if it was not found, zero is returned



  delay(1000);
}

Thanks in advance for any replies I receive!

Missing the ; here....

int frequency(char note)

Thanks! That also made me recheck the second int frequency(char note) later in the code and made me realize I put that in the wrong spot.