Expected initializer before void in function......

Forum 2005-2010 (read only) Software Syntax & Programs
1

When I try to compile the following code in Arduino 0015,I get the error "Expected initializer before void in function void loop()".How can I get the code to work?

byte myvar
void setup()
{
  myvar = 10
  Serial.begin (9600);
 }
void loop()
 {
   if (10 == HIGH)
   {
     Serial.println (myvar);
    }
   }
2

You need to have a semicolon at the end of each expression.

byte myvar;  // semicolon needed here
void setup()
{
  myvar = 10;   // and here
    Serial.begin (9600);
}
void loop()
{
  if (10 == HIGH)  
  {
    Serial.println (myvar);
  }
}

This code will compile but wont print anything because
if (10 == HIGH)
will never be true, what did you want to do here?

3

Thanks.By 10 I meant for it to be pin 10,oops forgot to define the input.

4

Arduino digital pins are inputs by default, although it does no harm to explicitly declare inputs in setup.

Your loop code could look like this:

void loop()
{
if (digitalRead(10) == HIGH)
{
Serial.println (myvar);
delay(100); // add a delay to reduce the number of times this prints.
}
}

5

ok,thanks