for a project, I am using the dvc100p by LEM to detect if the voltage goes over 50v.
but i am having issues understanding how to calculate the voltage conversion and how to use the reference pin in and out
I tried testing it with an input voltage of 5v and 9v but the output keeps coming to 5.4 which should not be possible
dvc_1000-p.pdf (1.3 MB)
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this sensor ????????????
im sorry
i was referring to the dvc1000p by lem
Post a simple schematic showing how you wired this and a link to the sensor giving technical information,
Code, error msgs, link to sensor, wiring diagram. That is what is needed.
dvc_1000-p.pdf (1.3 MB)
for the circuit i am powering it with a 9v battery and using a 5v regulator to power the dvc1000p
Here is the datasheet for the LEM DVC 1000-P voltage sensor.
The reference voltage is used to bias the output of the sensor to half the supply voltage, so that you can measure input voltages of either polarity.
An internal reference voltage is provided, but you don't have to use it, you can provide your own reference voltage if desired.
If you choose to use it, then you connect Ref_Out to Ref_In.
I used the internal reference voltage and wired it up as shown in the circuit diagram and I am using a multimeter to measure the output
I am getting 5.7v which should not be possible as the output it limited from 0.5 to 4.5
could it be that the sensor might be faulty or is there anything I'm missing
What does the output of the regulator measure?
You should have capacitors at the input and output of the regulator for stability and prevent an oscillation on the output.
See the regulator manufacturer's datasheet for their capacitor recommendations
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You need to check the regulator manufacturer's datasheets for there bypass requirements. Not all recommend the same bypass capacitors so it is best to check with the brand you are using. The other device is optional but I would add them anyway. What is your source of 9V, hopefully not a smoke alarm battery?
Umm ye I'm using a 9v battery
Is that a problem?
Generally yes, they do not supply enough energy and fail fairly rapidly nicking your pocket for more money. Every 1/2 hour measure the 9V battery voltage. Depending on the regulator chosen it may drop out of regulation when the input falls to 7V. This will give you an idea of where I am coming from. Note the cutoff for the 9V, your limit is 7V so most of the battery capacity will not be used.
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