//Automatic Nightlight
const int LED=9;
const int LIGHT=0;
const int MIN_LIGHT=200;
const int MAX_LIGHT=900;
int val = 0
void setup() {
pinMode(LED,OUTPUT);
}
void loop(){
val = analogRead(LIGHT);
val = map(val,MIN_LIGHT, MAX_LIGHT, 255,0);
val = constrain(val,0,255);
analogWrite(LED,val);
}
I am not Kreskin, what exactly should it do, and what does it do?
OMG, I don't understand it, either!
What uC are you using? Just as an example using an Arduino Uno Rev3 you can't use pin 1 oe pin 0 as an analog input which brings us to what light sensor is being used? How is it configured? A schematic would be nice. If you are measuring an analog value from your sensor you need to use an analog input.
Ron
Can you post a schematic? Are you using an LDR? Did you mean to use A0 rather than 0 for LIGHT? Have you tried printing out val after reading the value here?
val = analogRead(LIGHT);
const int LIGHT=0;
did you mean ?
const int LIGHT=A0;
Are you using a light dependent resistor to measure light in the room? Did you use an LDR module, an LDR configured as a voltage divider or just an LDR?
Where did these preset minMax limits come from? Do they actually represent the raw val = analogRead(LIGHT);
readings you empirically noted during LDR circuit testing and calibration?
Except
When you use the analogRead() function, "0" and "A0" refer to the same pin, the analog pin 0. These two invocations of analogRead() are equivalent: analogRead(0);
a7
@Delta_G @alto777 I didn't know analogRead() would interpret 0 as A0. Thanks for informing me about that. Now it all makes sense
Thanks a bunch, I also was not aware of that.
Ron
.
I understand this and if you ask a question I try to help you.
missing a ;
try
int val = 0;
The author didn't ask a single question, didn't even visit the thread once - why are you writing all this to him?
Sorry, please tell us the new rules of engagement. He may not be hovering over his keyboard, waiting with bated breath for pronouncements from the gods.
Me, I just saw the problem, so I identified it.
Apologies. I'll leave again.
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