Alright, when I verified it, I got this error message:
F05WE4KIG11YTGV.ino: In function 'void setup()':
F05WE4KIG11YTGV.ino:237:54: error: invalid conversion from 'int' to 'void (*)()' [-fpermissive]
And after many confused minutes, I got nothing. So, here's my 'void setup()', so please tell me what I did wrong:
void setup(){
pinMode(buttonPin,INPUT);
pinMode(PIN_READWRITE, OUTPUT);
digitalWrite(PIN_READWRITE, LOW);
pinMode(PIN_CONTRAST, OUTPUT);
digitalWrite(PIN_CONTRAST, LOW);
pinMode(PIN_BUTTON, INPUT);
digitalWrite(PIN_BUTTON, HIGH);
pinMode(PIN_AUTOPLAY, OUTPUT);
digitalWrite(PIN_AUTOPLAY, HIGH);
// Digital pin 2 maps to interrupt 0
attachInterrupt(0/*PIN_BUTTON*/, buttonPin, FALLING);
initializeGraphics();
lcd.begin(16, 2);
}[/color]
You're kidding, right? You're expecting someone here to do... what?
Regards,
Ray L.
Sorry, I miss clicked and couldn't fix that color for 5 minutes. Its fixed now.
Dan95
December 22, 2016, 12:55am
4
The attachinterrupt thing has a /* comment */ right in the middle of it.
The second argument to attachInterrupt is a pointer to the function that handles the interrupt. You are are passing buttonPin, which is obviously an int.
READ the first post in the forum: "How to use this forum - please read!"
Regards,
Ray L.
Dan95:
The attachinterrupt thing has a /* comment */ right in the middle of it.
That is actually not a problem...
attachInterrupt takes a function as a parameter, and you are passing it an int.
attachInterrupt(0/*PIN_BUTTON*/, buttonPin, FALLING);
What are you trying to do here? When the interrupt on pin 0 falls, you want the arduino to … what? You want it to buttonPin? What does that mean?
setup() {
attachInterrupt(0/*PIN_BUTTON*/, doThisWhenInterrupt0Falls, FALLING);
}
void doThisWhenInterrupt0Falls() {
// some code here
}
RayLivingston:
The second argument to attachInterrupt is a pointer to the function that handles the interrupt. You are are passing buttonPin, which is obviously an int.
Alright, my code is now:
pinMode(buttonPin,INPUT);
pinMode(PIN_READWRITE, OUTPUT);
digitalWrite(PIN_READWRITE, LOW);
pinMode(PIN_CONTRAST, OUTPUT);
digitalWrite(PIN_CONTRAST, LOW);
pinMode(PIN_BUTTON, INPUT);
digitalWrite(PIN_BUTTON, HIGH);
pinMode(PIN_AUTOPLAY, OUTPUT);
digitalWrite(PIN_AUTOPLAY, HIGH);
// Digital pin 2 maps to interrupt 0
attachInterrupt(0, int buttonPin, FALLING);
initializeGraphics();
lcd.begin(16, 2);
Which solved my previous error, but it causes this error:
expected primary-expression before 'int'
Dan95
December 22, 2016, 2:10am
9
RayLivingston:
That is actually not a problem...
I see that now that you mention it, duh, not sure what I was thinking.