Joystick with 4 inputs, but can turn on 2 LED diodes at the same time.

So to intoduce you, this is a school project were I use diodes instead of motors to see how the joystick works. But there is a problem with the joystick, you can use two inputs at the same time. Is there a way to write the code so if more than one input is used it won't turn on any LED.
Sorry for any grammar or spelling mistakes, and thanks in advance!

//Sætter nogle konstanter, som ikke kan ændres. Konstaterne bruges til, at definere portene på de forskellige ledpinde og joystikket.

const int joy1 = 1;
const int joy2 = 2;
const int joy3 = 3;
const int joy4 = 4;
const int led1 = 13;
const int led2 = 12;
const int led3 = 11;
const int led4 = 10;


// Starter forskellige variabler til, at være slukket.  
int joy1Status = 0;
int joy2Status = 0;
int joy3Status = 0;
int joy4Status = 0;
void setup(){
  
  //Definere alle forskellige indgange, hvorvidt det skal være input og output.
  pinMode(joy1, INPUT);
  pinMode(joy2, INPUT);
  pinMode(joy3, INPUT);
  pinMode(joy4, INPUT);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
  pinMode(led4, OUTPUT);
}
void loop(){
  //Læser alle joystikkets inputs, hvorvidt de er i brug eller ej.  
  
 joy1Status = digitalRead(joy1);  
 joy2Status = digitalRead(joy2); 
 joy3Status = digitalRead(joy3);
 joy4Status = digitalRead(joy4);
  
  
  //Hvis den første joystik port bliver brugt, skal den første pære skal tændes. (Dette er til højre)
 if(joy1Status == HIGH){
   digitalWrite(led1, HIGH);
   digitalWrite(led2, LOW);
   digitalWrite(led3, LOW);
   digitalWrite(led4, LOW);
 }
 else{
   digitalWrite(led1, LOW);
 }

 //Hvis den anden joystik port bliver brugt, den anden pære skal tændes.(Dette er ned)
 if(joy2Status == HIGH){
   digitalWrite(led2, HIGH);
   digitalWrite(led1, LOW);
   digitalWrite(led3, LOW);
   digitalWrite(led4, LOW);
 }
 else{
   digitalWrite(led2, LOW);
 }
 //Hvis den tredje joystik port bliver brugt, den tredje pære skal tændes. (Dette er venstre)
 if(joy3Status == HIGH){
   digitalWrite(led3, HIGH);
   digitalWrite(led2, LOW);
   digitalWrite(led1, LOW);
   digitalWrite(led4, LOW);
 }
 else{
   digitalWrite(led3, LOW);
 }
 //Hvis den fjerde joystik port bliver brugt, den fjerde pære skal tændes. (Dette er op)
 if(joy4Status == HIGH){
   digitalWrite(led4, HIGH);
   digitalWrite(led2, LOW);
   digitalWrite(led3, LOW);
   digitalWrite(led1, LOW);
 }
 else{
   digitalWrite(led4, LOW);
   
 }
 if(joy1Status == HIGH && joy2Status == HIGH)
  {
   digitalWrite(led1, LOW);
   digitalWrite(led2, LOW);
   digitalWrite(led3, LOW);
   digitalWrite(led4, LOW); 
  }
 
 }

pictures of the breadboard
Imgur

Is there a way to write the code so if more than one input is used it won't turn on any LED.

One way would be to add all the joystick inputs together. If the total is anything other than 1 then turn off all the LEDs, else examine each input to find out which one HIGH and turn on the corresponding LED.

What kind of joystick are you using? Generally, joysticks are read using two analog pins - one for the x direction and one for the y direction.