I already tried searching this but I keep seeing different answers.
I need at least 1A from the +5V output due to using a lot of components from this source, otherwise, I will have to use a separate voltage regulator circuit to bring down 20V or 24V to +5V.
The max. current depends on the heat dissipation in the voltage regulator. If you have to bring 20V (can the board handle that?) down to 5V, you already have a massive disadvantage compared to e.g. a 9V power supply.
I don't have numbers, but I would certainly opt for an external power supply to supply 5V to the peripherals and the board.
The maximum total current you can draw when the device is powered via external power supply is 1A for the Arduino Uno, 800mA for the Due and 500mA for the Nano:
DC Jack is connected, through a diode, to Vin.
Vin is stepped down to 5V on-board.
5V is stepped down to 3V3 on board.
Thus you can do any one of the following numbered items.
Connect a 7-12V supply to the DC Jack; thus:
• use Vin as a supply @ DC - 0.7V for off-board peripherals, and
• use 5V as a supply for off-board peripherals, and
• use 3V3 as a supply for off-board peripherals.
Connect a 6-12V supply to Vin; thus:
• use 5V as a supply for off-board peripherals, and
• use 3V3 as a supply for off-board peripherals.
Connect 5V supply to the 5V; thus:
• use 3V3 as a supply for off-board peripherals.
The above is only guaranteed for boards that follow the reference schematic, as plenty of clone/compatible boards do. If you buy a cheap Chinarduino and something doesn't work, or the thing breaks, after following anything above then that's your tough luck:
ard_newbie:
The maximum total current you can draw when the device is powered via external power supply is 1A for the Arduino Uno, 800mA for the Due and 500mA for the Nano:
Wow. A lot of things are swept under the carpet here.
Sounds like useless statements on the first page of a Texas Instruments datasheet.
Leo..
Arduido Due has a LM2734, so the maximum current teorically is 1A in 5V pin. Is this correct?
Thanks.
ard_newbie:
The maximum total current you can draw when the device is powered via external power supply is 1A for the Arduino Uno, 800mA for the Due and 500mA for the Nano:
DC Jack is connected, through a diode, to Vin.
Vin is stepped down to 5V on-board.
5V is stepped down to 3V3 on board.
Thus you can do any one of the following numbered items.
Connect a 7-12V supply to the DC Jack; thus:
• use Vin as a supply @ DC - 0.7V for off-board peripherals, and
• use 5V as a supply for off-board peripherals, and
• use 3V3 as a supply for off-board peripherals.
Connect a 6-12V supply to Vin; thus:
• use 5V as a supply for off-board peripherals, and
• use 3V3 as a supply for off-board peripherals.
Connect 5V supply to the 5V; thus:
• use 3V3 as a supply for off-board peripherals.
The above is only guaranteed for boards that follow the reference schematic, as plenty of clone/compatible boards do. If you buy a cheap Chinarduino and something doesn't work, or the thing breaks, after following anything above then that's your tough luck:
The Due has indeed a switching regulator (MPM3610 on the diagram) between DC socket/Vin and the 5volt rail,
and is therefore more capable than the Uno and Nano.
Leo..