Need helping understanding a DTH11 sensor

[catpop]

So basically I was following a tutorial and it uses a pull-off resistor, and it makes sense to me why he used it, so I started building my circuit and programming it, it works fine, but when I remove the 10ku resistor the circuits continue and the arduino can read values, so resistor makes no difference, but why?

One possible explanation: Is that the sensor always allow current to flow in it, So the pin 2 always send some voltage to the arduino, then he can read and dont go crazy.

schematic of the circuit:

[ruilviana]

Are you using modules or device?

[catpop]

first image DTH11, 3 pins

[ruilviana]

This kind of modules, (first image), has restores built into the PCB.

Se the next images.

[catpop]

Im gonna send you a picture.

[catpop]

What does that means?

[ruilviana]

What's written on the piece I marked in red?

And I couldn't read.

[catpop]

the chip have a number, 512, on the side (on the board) R1, and a "S" in the front

[ruilviana]

OK. 512 means = 5 1 zero 2 zeros = a resistor of 5000 Ohms = 5K.
Sorry Mrs @jim-p is wright. may fault .
Correct 5 1 2 zeros = a resistor of 5100 Ohms = 5K1.
Look here:
https://www.mouser.com/datasheet/2/758/DHT11-Technical-Data-Sheet-Translated-Version-1143054.pdf
Chapter 3.

[catpop]

okok.

[jim-p]

Actually 5.1K or 5100

[catpop]

So that resistor does the job of the pull off resistor and so i dont need to add one?

[ruilviana]

Correct.

[GolamMostafa]

@ruilviana

Correct 5 1 2 zeros = a resistor of 5100 Ohms = 5K1.

===> 51x10²
===> 5100 ohm
===> 5.1 kohm